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Ede4ka [16]
2 years ago
11

In your lab you are studying the genome of venomous rattlesnakes to find the gene which codes for their venom glands. One rattle

snake has a mutation and cannot produce venom. You compare his DNA to a normal rattlesnake. What type of mutation has occurred?
Normal: AATCGCTACGCACGTCAG
Mutated: AATCGCCATGCACGTCAG
A. Point mutation
B. Inversion
C. Deletion
D. Insertion
Biology
1 answer:
gogolik [260]2 years ago
4 0

Answer:

I believe your answer is inversion. Hope this helps.

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Help please! DNA Assignment
vovangra [49]

Answer:

DNA Replication:

Replicate the following strand of DNA:

Original DNA: A T G A A C CA T T C A G T A T G G

Complementary DNA:

Remember that the complimentary base pairs in DNA are Adenine-Thymine and Guanine-Cytosine, or A-T and G-C. This means that if the original sequence is:

A T G A A C C A T T C A G T A T G G

Then the compliment is (replace with the opposite base pairs):

T A C T T G G T A A G T C A T A C C

Transcription:

Transcribe the DNA to make an mRNA molecule

COMPLIMENTARY DNA:

mRNA Molecule:

So if our complimentary DNA (antisense stand) is T A C T T G G T A A G T C A T A C C then to transcribe, we basically create another complimentary strand, but for mRNA, we use Uracil instead of Thymine:

A U G A A C C A U U C A G U A U G G  

Translation:

Translate the mRNA into the corresponding amino acids.

mRNA MOLECULE:

AMINO ACID:

Using the DNA sequence provided, determine the amino acids.

Next, take each codon (3-base set) to the table and record the corresponding protein:

A U G = Methionine (start)

A A C = Asparagine

C A U = Histidine

U C A = Serine

G U A = Valine

U G G = Tryptophan

ORIGINAL DNA: A T G G G T C T A G C G A A A G A T

Complementary DNA:

mRNA DNA Molecule:

Amino Acid:

And we do it all again:

A T G G G T C T A G C G A A A G A T = original DNA

T A C C C A G A T C G C T T T C T A = complementry DNA

A U G G G U C U A G C G A A A G A U = mRNA

A U G = Methionine (start)

G G U = Glysine

C U A = Leucine

G C G = Alanine

A A A = Lysine

G A U = Aspartate

Explanation:

4 0
3 years ago
How does a eukaryotic organism differ from a prokaryotic organism
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The answer is <span>0.132606 amu.</span>

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mass of a neutron: 1.00866 amu
</span>
An oxygen atom has 8 protons and 8 neutrons. Therefore:
Δm = 8 · 1.00728 + 8 · 1.00866 - <span>15.994914 = 8.05824 + 8.06928 - 15.994914 = 0.132606 amu
</span>
5 0
3 years ago
Read 2 more answers
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