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Vladimir79 [104]
2 years ago
15

What is the annual gross for a full-time employee who makes $ 25.25 an hour?

Mathematics
2 answers:
Ksju [112]2 years ago
7 0

Per Day. 25.25 x 24 is 606

Per Week. 606 x 7 is 4242

Per Month. 25.25 x 31 is 782.75

Per Year. 782.75 x 12 is 9393

LenaWriter [7]2 years ago
5 0

Answer:

52,520

Step-by-step explanation:

So a full time employee works 40 hours a week (8 hours a day).  Their are 52 weeks in a year.  When you multiply $25.25 * 40 hours your get $1,010.  Then take the $1,010 and multiply by the number of weeks in the year.  $1,010*52 which is 52,520.

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Lauren's scores on her math tests are, 93, 91, 98, 100, 95, 92 , and 96. What score could Lauren get on he next math test so tha
Ugo [173]
First you need to find the mean & median:
mean:
93 + 91 + 98 + 100 + 95 + 92 + 96 = 665
665 / 7 = 95
median:
<u>91</u>, <em>92</em>, <u>93</u>, 95, <u>96</u>, <em>98</em>, <u>100</u>
95

Because the mean and median are the same, her next test score should be 95. The average of the current average and 95 (her next test score) is 95, so that will remain the same. If you add 95 to the median list,the median will still be 95. The same goes for the mean.Her next test score should be 95.
7 0
3 years ago
Maths!
Ber [7]

Answer:

(1) Variance = 4.5 and Standard deviation = 2.121.

(2) Variance = 4.5 and Standard deviation = 2.121.

(3) The effect on the measure of dispersion if each value is changed uniformly ​is that it remains unchanged.

Step-by-step explanation:

We are given with the following set of data below;

              X                     X-\bar X                   (X-\bar X)^{2}

              5                   5 - 8 = -3                     9

              5                   5 - 8 = -3                     9

              8                   8 - 8 = 0                      0

             10                  10 - 8 = 2                     4

             10                  10 - 8 = 2                     4

             10                  10 - 8 = 2                     4

              9                   9 - 8 = 1                       1

              9                   9 - 8 = 1                       1

         <u>     6     </u>              6 - 8 = -2             <u>        4       </u>          

Total <u>    72     </u>                                         <u>       36       </u>

<u>Firstly, the mean of the above data is given by;</u>

              Mean, \bar X  =  \frac{\sum X}{n}

                              =  \frac{72}{9}  = 8

(1)Now, the variance of the given data is;

            Variance  =  \frac{\sum (X-\bar X)^{2} }{n-1}

                                  =  \frac{36}{9-1}  = 4.5

So, the standard deviation, (S.D.)  =  \sqrt{\text{Variance}}

                                                        =  \sqrt{4.5} = 2.12

(2) Now, each value is added by 2; so the new data set is given by;

              X                     X-\bar X                   (X-\bar X)^{2}

              7                   7 - 10 = -3                     9

              7                   7 - 10 = -3                     9

             10                  10 - 10 = 0                     0

             12                  12 - 10 = 2                     4

             12                  12 - 10 = 2                     4

             12                  12 - 10 = 2                     4

              11                  11 - 10 = 1                       1

              11                  11 - 10 = 1                       1

         <u>     8     </u>              8 - 10 = -2             <u>        4       </u>          

Total <u>    90     </u>                                         <u>       36       </u>

<u>Firstly, the mean of the above data is given by;</u>

              Mean, \bar X  =  \frac{\sum X}{n}

                              =  \frac{90}{9}  = 10

(1)Now, the variance of the given data is;

            Variance  =  \frac{\sum (X-\bar X)^{2} }{n-1}

                                  =  \frac{36}{9-1}  = 4.5

So, the new standard deviation, (S.D.)  =  \sqrt{\text{Variance}}

                                                                =  \sqrt{4.5} = 2.12

(3) The effect on the measure of dispersion if each value is changed uniformly ​is that it remains unchanged as we see in the case of variance or standard deviation.

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WITCHER [35]

Answer:

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Step-by-step explanation:

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4 0
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