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3 years ago

12

if atom X has 6 protons,6 neutrons and 6 electrons and aton Z has 6 protons,7neutrons and 6 electrons,atom x and atom z are isot

opes of the element

1 answer:

MakcuM [25]3 years ago

3 0

The answer is 89! okay thank you

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Helppp!!!!!! pleaseeee

Ugo [173]

Answer:

A

Explanation:

you need to make a punnent squere

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5 0

3 years ago

In the simple act of lighting a match, chemical energy stored in the match head is transformed into heat and light. What is true

harina [27]

The head of a matchstick has a great deal of chemical energy stored in it, including combustible substances that produce a flame when rubbed against a suitable surface. ... As the combustible materials burn, some of the chemical energy is transformed into heat energy, and some is transformed into light energy. Hope this helps

5 0

3 years ago

Read 2 more answers

A 1.28-kg sample of water at 10.0 °C is in a calorimeter. You drop a piece of steel with a mass of 0.385 kg at 215 °C into it. A

Kryger [21]

Answer:

$T_{2}=16,97^{\circ}C$

Explanation:

The specific heats of water and steel are

$Cp_{w}=4.186 \frac{KJ}{Kg^{\circ}C}$

$Cp_{s}=0.49 \frac{KJ}{Kg^{\circ}C}$

Assuming that the water and steel are into an <em>adiabatic calorimeter</em> (there's no heat transferred to the enviroment), the temperature of both is identical when the system gets to the equilibrium $T_{2}_{w}= T_{2}_{s}$

An energy balance can be written as

$m_{w}\times Cp_{w}\times (T_{2}- T_{1})_{w}= -m_{s}\times Cp_{s}\times (T_{2}- T_{1})_{s}$

Replacing

$1.28Kg\times 4.186\frac{KJ}{Kg^{\circ}C}\times (T_{2}-10^{\circ}C)= -0.385Kg\times 0.49 \frac{KJ}{Kg^{\circ}C} \times (T_{2}-215^{\circ}C)$

Then, the temperature $T_{2}=16,97^{\circ}C$

8 0

3 years ago

A certain element has 52 protons, 52 electrons, and 76 neutrons. its atomic mass is _____. 52 76 128 104

kifflom [539]

Pretty sure it is 128 hope this helps you :D

5 0

3 years ago

Read 2 more answers

A 2.10 L vessel contains 4.65 mol of nitrous oxide (N2O) at 3.82 atm. What will be the pressure of this gas in a container that’

sveticcg [70]

Answer:

The answer to your question is 7.64 atm

Explanation:

Data

Volume 1 = V1 = 2.1 l

moles = 4.65

Pressure 1 = P1 = 3.82 atm

Volume 2 = Volume 1/2

Pressure 2 = ?

Process

1.- Calculate the new volume

Volume 2 = 2.10/2

Volume 2 = 1.05 l

2.- Use Boyle's law to find the Pressure

P1V1 = P2V2

-Solve for P2

P2 = P1V1 / V2

-Substitution

P2 = (3.82)(2.1) / 1.05

-Simplification

P2 = 8.022/1.05

-Result

P2 = 7.64 atm

4 0

3 years ago