<u>3.04 </u> liters of propane(C₃H₈) are needed to react with 15.2 liters of oxygen to produce water and carbon dioxide
Explanation:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
The mole ratio between the propane and oxygen in the equation is 1 : 5 as can be seen in the equation.
If the amount of O₂ reacting is 15.2 L then the amount of propane required is;
1 : 5
X : 15.2
We cross multiply the ration
5x = 15.2 * 1
X = 15.2/5
X = 3.04
= 3.04 L
Answer:
Eukaryotic (a plant cell)
Explanation:
The presence of a chloroplast indicates that the cell has membrane-bound organelles. This is not a feature of prokaryotic cells - only eukaryotic cells. Therefore, the cell is eukaryotic. The presence of a large vacuole, chloroplast, and rigid cell wall suggests its a plant cell as plant cells are the only eukaryotes with these features.
The answer to this question would be: 11.5 grams
The molecular mass of hydrogen is 1, oxygen is 16 and carbon is 12. Then the molecular mass of CH4O would be: 12 + 4(1) + 16= 32.
To find the hydrogen mass, you just need to divide the hydrogen with total mass, resulting in the mass ratio of hydrogen to the compound. Then the amount of hydrogen inside 92 gram of CH4O are: 92grams * (4/32)= 11.5 grams
<u>Answer:</u> The number of moles of gas present are 0.390 moles
<u>Explanation:</u>
To calculate the number of moles of gas, we use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 0.868 atm
V = Volume of the gas = 11 L
T = Temperature of the gas =
R = Gas constant =
n = number of moles of gas = ?
Putting values in above equation, we get:
Hence, the number of moles of gas present are 0.390 moles
I’m pretty sure you add, multiply, subtract, & divide