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Molar Mass KI => 166.003 g/mol
* number of moles:
n = mass of solute / molar mass
n = 49.8 / 166.003
n = 0.3 moles KI
Therefore:
M = n / V
M = 0.3 / 1.00
M = 0.3 mol/L
hope this helps!
Answer:
The correct answer is c) 134L
Explanation:
We use the formula PV =nRT. The normal conditions of temperature and pressure are 273K and 1 atm, we use the gas constant = 0, 082 l atm / K mol.
1 atm x V = 5, 98 mol x 0, 082 l atm / K mol x 273 K
V = 5, 98 mol x 0, 082 l atm / K mol x 273 K / 1 atm
V = 133, 86828 l
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Answer:
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Explanation: