1.20x1,024=1228.8 this is your answer.
hope that this helps.
B false i think, i may be wrong
The answer is:
The rate constant K2 = 1.9 x 10^-4 1/s
The explanation:
According to Arrhenius equation:
ln(k₁/k₂) = Ea/R (1/T₂ - 1/T₁)
when K is the rate constant
and Ea is the activation energy
R is the ideal gas constant
T1 & T2 is a temperature at kelvin
when we have:
Ea = 272 KJ = 272000 J
R is the ideal gas constant 8.3145 J/Kmol
K1 = 2.3 x 10^-5 1/s K2 = ?? that is we need to calculate
T1 = 718 K T2 =753 K
So by substitution:
ln(k₁/k₂) = Ea/R (1/T₂ - 1/T₁)
㏑(2.3X10^-5/K2) = [272000/8.314](1/753-1/718)
∴ K2 = 1.9 x 10^-4 1/s
Answer:
Y AND Z
HOPE IT HELPS THANK ME LATER.
