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gtnhenbr [62]
4 years ago
14

How many atoms are present in 179.0 g of iridium? include units please:)!

Chemistry
2 answers:
pentagon [3]4 years ago
6 0

Answer:

A. 5.606x10²³atoms

Explanation:

denpristay [2]4 years ago
5 0

Answer:

179.0 g of iridium (1 mol / 192.217 g) ( 6.022 x 10^23 atoms /  1 mol ) = 5.61 x 10^23 atoms of iridium

Explanation:

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