I’d say for the answer 13.13 mmHg?
Answer:
4.86moles of barium sulfide are produced
Explanation:
To solve this question we need to convert the mass of barium sulfide (BaS) to moles using the molar mass of BaS:
<em>Molar mass BaS:</em>
<em>1 Ba atom = 137.3g/mol</em>
<em>1 S atom = 32.1g/mol</em>
<em>Molar mass BaS = 137.3 + 32.1 = 169.4g/mol</em>
<em />
<em>Moles in 823g of BaS:</em>
823g * (1mol / 169.4g) =
<h3>4.86moles of barium sulfide are produced</h3>
Precision relates to how close the answers are to each other, so I’d think it would be D because of the limited range between data points.
To get the number of gold atoms, you have to divide the mass of the gold by the mass of the gold atom. It follows this simple equation

.
Let x be the number of gold atoms. Plug in the values to a calculator.
x =

Both have the same units so the unit gram(g) can be cancelled.
x then would be equal to 1.53x10^22. So there are 1.53x10^22 atoms of gold in 5 g of gold