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Serhud [2]
3 years ago
5

Choose the equation that matches the following situation: For a field trip, 24 students rode in cars and the rest filled three b

uses. How many students were in each bus if 96 students were on the trip?
24b + 3 = 96
27b = 96
24 = 3b + 96
96 = 24 +3b
Mathematics
1 answer:
olchik [2.2K]3 years ago
8 0

Answer:

96 = 24 + 3b

96 students in all, 24 in cars and the rest in 3 buses

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Delia has 3 5/8 yards of ribbon. About how many 1/4 yard-long pieces can she cut?
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Wait is it not at all 14.5 or 14 1/2 Because with the math I did I got 14 1/2

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2 years ago
Natalia begins to find the mean absolute deviation of this data set. She finds the mean of the data and then finds the distance
s2008m [1.1K]
Hello!

To calculate mean absolute deviation, you find the mean, find the distance between each data point and the mean, add up those distances, and divide by the number of data points.

In this scenario, after Natalia finds the distances, she must add them all up and then divide by the number of data points.

I hope this helps!
3 0
3 years ago
Read 2 more answers
4.6363 as fraction using long division
nirvana33 [79]

Answer:

459/99

Step-by-step explanation:

0.6363... is equal to 63/99.

We want to add 4.

4 = 396/99

396/99 + 63/99 = 459/99

We can double check with a calc.

5 0
3 years ago
a hot tub pump circulate 4 cubic feet of water per minute, how many cubic inches of water does it circulate earch minute?
Shtirlitz [24]

4 {ft  }^{3}  \times  {( \frac{12in}{ft} )}^{3}  = 6912 {in}^{3}

4 0
2 years ago
The height of a punted football can be modeled with the quadratic function 0.01x^2 + 1.18x+2.
Fantom [35]

The function of the path of the punted ball is a quadratic function which

follows the path of a parabola.

The correct responses are;

Part A: The coordinates of the vertex is \underline {(59, \, 36.81)}

Part B: The maximum height of the punt is <u>36.81 ft.</u>

Part C: The defensive player must reach up to <u>7.65 feet</u> to block the punt.

Part D: The distance down the field the ball will go without being blocked is approximately <u>119.67 ft.</u>

<u />

Reasons:

The function for the height of the punted ball is; h = -0.01·x² + 1.18·x + 2

Assumption; The distances are feet.

Part A: By completing the square, we have;

f(x) = -0.01·x² + 1.18·x + 2

100·f(x) = -x² + 118·x  + 200

-100·f(x) = x² - 118·x  - 200

x² - 118·x + (118/2)²= 200 + (118/2)²

(x - 59)² = 200 + (59)² = 3681

(x - 59)² - 3681

At the vertex, -3281 = -100·f(x)

∴ f(x) at the vertex = -3681/-100 = 36.81

\mathrm{\underline{Coordinate \ of \ the \ vertex = (59, \, 36.81)}}

Part B: The maximum height is given by the y-value at the vertex = 36.81 ft.

Part C: When <em>x</em> = 5, we have;

h = -0.01·x² + 1.18·x + 2

h = -0.01 × 5² + 1.18 × 5 + 2 = 7.65

The defensive player must reach up to 7.65 feet to block the punt

Part D: The distance the ball will go before it hits the ground is given by

the function, for the height as follows;

h = -0.01·x² + 1.18·x + 2 = 0

From the completing the square method, above, we get;

-0.01·x² + 1.18·x + 2 = 0

x² - 118·x  - 200 = 0

x² - 118·x + (118/2)²= 200 + (118/2)²

x² - 118·x + (59)²= 200 + (59)² = 3681

(x - 59)² = 3681

x - 59 = ±√3681

x = 59 ± √3681

x = 59 + √3681 ≈ 119.67

The distance down the field the ball will go without being blocked, x ≈ <u>119.67 ft.</u>

<u />

Learn more here:

brainly.com/question/24136952

5 0
2 years ago
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