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3 years ago

What is the electric potential 20.0 cm from a negative point charge of 15 µC?

Physics

1 answer:

Len [333]3 years ago

4 0

Answer: V = 675000v

Explanation:

Electric potential V can be calculated by using the formula

V = Kq/r

Where

V = electric potential

q = charge = 15µC

K = Coulomb constant = 9 × 10^9Nm^2C^-2

r = 20 cm

Substitute all the parameters into the formula

V = (9×10^9 × 15×10^-6)/20×10^-2

V = 135000/0.2

V = 675000 volt

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Answer:

The resultant force would (still) be zero.

Explanation:

Before the 600-N force is removed, the crate is not moving (relative to the surface.) Its velocity would be zero. Since its velocity isn't changing, its acceleration would also be zero.

In effect, the 600-N force to the left and 200-N force to the right combines and acts like a 400-N force to the left.

By Newton's Second Law, the resultant force on the crate would be zero. As a result, friction (the only other horizontal force on the crate) should balance that 400-N force. In this case, the friction should act in the opposite direction with a size of 400 N.

When the 600-N force is removed, there would only be two horizontal forces on the crate: the 200-N force to the right, and friction. The maximum friction possible must be at least 200 N such that the resultant force would still be zero. In this case, the static friction coefficient isn't known. As a result, it won't be possible to find the exact value of the maximum friction on the crate.

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The mechanical work done by the sprinter during this time will be 4537.5 J , the average power the sprinter must generate will be 907.5 W and if the sprinter converts food energy to mechanical energy with an efficiency of 25% then he will be burning calories at 54.20 calories per second.

Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. It is frequently described in its most basic form as the result of force and displacement.

The quantity of energy moved or transformed per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units.. A scalar quantity is power.

Given 75-kg sprinter accelerates from rest to a speed of 11.0 m/s in 5.0 s.

So let,

m = 75 kg

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t = 5.0 s

So the mechanical work done by the sprinter during this time will be as follow:

W = 0.5 mv²

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The average power the sprinter must generate will be as follow:

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Learn more about mechanical power here:

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