3 years ago

What is the electric potential 20.0 cm from a negative point charge of 15 µC?

Physics

1 answer:

Len [333]3 years ago

4 0

Answer: V = 675000v

Explanation:

Electric potential V can be calculated by using the formula

V = Kq/r

Where

V = electric potential

q = charge = 15µC

K = Coulomb constant = 9 × 10^9Nm^2C^-2

r = 20 cm

Substitute all the parameters into the formula

V = (9×10^9 × 15×10^-6)/20×10^-2

V = 135000/0.2

V = 675000 volt

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Find the total electric charge of 1.7 kg of electrons. me=9.11×10−31kg, e=1.60×10−19C.

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Answer:

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Explanation:

The mass of one electron is

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So the number of electrons contained in M=1.7 kg of mass is

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$Q=Ne=(1.87\cdot 10^{30})(1.6\cdot 10^{-19}C)=2.99\cdot 10^{11}C$

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