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3 years ago

LABORATORY TITLE:

Physics

1 answer:

mezya [45]3 years ago

5 0

Answer:

PAPER CLIPS ON NOSE OF A PAPER AIRPLANE

Purpose: To determine if the number of paperclips on the nose of a paper airplane affects the velocity and speed, measured in meters per seconds.

Make a Hypothesis Based on the Learning Thus Far: If the number of paperclips on the nose of a paper airplane increases, then the speed will _increase______ (increase, decrease, stay the same) in a __linear_______ (linear, exponential, logarithmic) mathematical relationship, and the velocity will (increase, decrease, stay the same) in a __exponential____ (linear, exponential, logarithmic) mathematical relationship. (Fill in the appropriate words for your hypothesis.)

Pictures: Insert at least 3 pictures of yourself conducting the experiment into this lab report. At least 2 pictures must show your face as you conduct the investigation. You may need to ask someone to help take these photos.

Explanation:

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A block of mass m rests on a frictionless, horizontal surface. A cord attached to the block passes over a pulley whose radius is

ra1l [238]

Answer:

Explanation:

Let the tension in the cord be T₁ and T₂ .

for motion of block placed on horizontal table

T₁ = m a , a is acceleration of the whole system .

for motion of hanging bucket of mass m

mg - T₂ = ma

adding the two equation

mg + T₁- T₂ = 2ma

for rotational motion of the pulley

torque = moment of inertia x angular acceleration

(T₂ - T₁) R = I x α , I is moment of inertia of pulley , α is angular acceleration .

(mg - 2ma ) R = I x α

(mg - 2ma ) R = I x a / R

(mg - 2ma ) R² = I x a

mgR² = 2ma R² + I x a

a = mgR² / (2m R² + I )

Since body moves by distance d in time T

d = 1/2 a T²

a = 2d / T²

mgR² / (2m R² + I ) = 2d / T²

mgR²T² = 2d x (2m R² + I )

mgR²T² - 4dm R² = 2dI

m R² ( gT² - 4d ) = 2dI

I = m R² ( gT² - 4d ) ] / 2d .

3 0

4 years ago

A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.7 1010 m (inside the orbit

Lubov Fominskaja [6]

Answer:

58515.9 m/s

Explanation:

We are given that

$d_1=4.7\times 10^{10} m$

$v_i=9.5\times 10^4 m/s$

$d_2=6\times 10^{12} m$

We have to find the speed (vf).

Work done by surrounding particles=W=0 Therefore, initial energy is equal to final energy.

$K_i+U_i=K_f+U_f$

$\frac{1}{2}mv^2_i-\frac{GmM}{d_1}=\frac{1}{2}mv^2_f-\frac{GmM}{d_2}$

$\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2}=\frac{1}{2}v^2_f$

$v^2_f=2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})$

$v_f=\sqrt{2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})}$

Using the formula

$v_f=\sqrt{v^2_i+2GM(\frac{1}{d_2}-\frac{1}{d_1})}$

$v_f=\sqrt{(9.5\times 10^4)^2+2\times 6.7\times 10^{-11}\times 1.98\times 10^{30}(\frac{1}{6\times 10^{12}}-\frac{1}{4.7\times 10^{10})}$

Where mass of sun= $M=1.98\times 10^{30} kg$

$G=6.7\times 10^{-11}$

$v_f=58515.9 m/s$

4 0

3 years ago

Amber is a (a) metal (b) rubber (c) resin (d) sugar

zlopas [31]

Answer:

c. Resin.

Explanation:

Amber is a resin.

4 0

2 years ago

Alicia is solving a math equation. She is using her _____.

WITCHER [35]

I believe it is C. Medulla

I hope this helps you :)
Sorry if i was wrong

7 0

3 years ago

Read 2 more answers

One type of slingshot can be made from a length of rope and a leather pocket for holding the stone. The stone can be thrown by w

Valentin [98]

Answer:

ω = 10.75 rad/s

Explanation:

The stone leaves the circular path with a horizontal speed

v₀ = vt = R*ω

ω = v₀ / R

we are given that R = x / 25.7 so ω = 25.7*v₀ / x

Kinematics gives x = v₀*t

With this substitution for x the expression for ω becomes ω = 25.7 / t

Kinematics also gives for the vertical displacement y that

y = v₀y*t + 0.5*ay*t²

we know that v₀y = 0 m/s

since the stone is launched horizontally, so that

y = 0.5*ay*t² ⇒ t = √(2*y / ay)

Using this result for t in the expression for ω and assuming that upward is positive, we get

ω = 25.7 / √(2*y / ay)

⇒ ω = 25.7 / √(2*(-28) / (-9.8))

⇒ ω = 10.75 rad/s

5 0

3 years ago