Answer:
I = W / 4π R_{s}², P = W / 2π c R_{s}², Io /I_{earth} = 10⁴
Explanation:
The intensity is defined as the ratio between the emitted power and the area of the spherical surface
I = P / A
Since the emitted power is constant and has a value of W for this case, let's look for the area of the sphere on the surface of the sun
A = 4π
²
I = W / 4π R_{s}²
.- The radiation pressure for total absorption is
P = S / c
Where S is the Pointer vector that is equal to the intensity
Let's replace
P = W / 2π c R_{s}²
.- We repeat for r = R_{s}/2
I₂ = W / 4π (R_{s}/ 2)²
I₂ = 4 W / 4π R_{s}²
I₂ = 4 Io
I₀ = W / 4piRs2
We calculate the radiation pressure
P₂ = I₂ / c
P₂ = 4 I₀ / c
P₂ = 4 (W / 4pi c Rs2)
.- the relationship between these magnitudes is
I₂ / I₀ = 4
P₂ / P₀ = 4
Let's calculate the intensity on the surface where the Earth is
r = 1.50 10¹¹ m
= W / 4π r²
Io / I_{earth} = r² /
²
Io /I_{earth} = (1.5 10¹¹ / 6.96 10⁸) 2
Io /I_{earth} = 4.6 10⁴
Io /I_{earth} = 10⁴
Each energy level has at least one orbital with two electrons. Energy level two can have two subleves and two orbits. But the maximum orbits are 7!
Answer:
The heat loss during the process = -4000 J
Explanation:
Work done by the student (W) = - 1000 J
Negative sign on the system is due to work done on the system.
Decrease in internal energy (U) = - 3000 J
We know that heat transfer in the system is given by (Q) = U + W
⇒ Q = - 1000 - 3000
⇒ Q = - 4000 J
This is the value of heat transfer during the process And negative sign indicates that heat loss during the process.
Answer:
Explanation:36.05 km
Given
First car travels
South
then turns and travels
east
Suppose south as negative y axis and east as positive x axis
So, ![r_1=-20\hat{j}](https://tex.z-dn.net/?f=r_1%3D-20%5Chat%7Bj%7D)
![r_2=30\hat{i}](https://tex.z-dn.net/?f=r_2%3D30%5Chat%7Bi%7D)
Displacement is the shortest between initial and final point
Dispalcement![=r=r_1+r_2](https://tex.z-dn.net/?f=%3Dr%3Dr_1%2Br_2)
Displacement![=-20\hat{j}+30\hat{i}](https://tex.z-dn.net/?f=%3D-20%5Chat%7Bj%7D%2B30%5Chat%7Bi%7D)
Displacement![=30\hat{i}-20\hat{j}](https://tex.z-dn.net/?f=%3D30%5Chat%7Bi%7D-20%5Chat%7Bj%7D)
Magnitude ![=\sqrt{30^2+(-20)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B30%5E2%2B%28-20%29%5E2%7D)
Magnitude![=36.05\ km](https://tex.z-dn.net/?f=%3D36.05%5C%20km)