Answer:
Explanation:
The rectangular components of a vector 
having a magnitude v and angle θ are:
The golf ball has an initial speed of 75 m/s at an angle of 60 degrees.
The variables of the equations have the values:
v = 75 m/s
θ = 60°
Substituting into the formula:
Without specifying units and with precision to the hundredths place:
Alot? You didn’t show me any work to solve
Atomic number, atomic mass
Answer:
The magnitud of the torque doing by the foot at the point where the shaft is attached is 0.063 Nm
Explanation:
The torque is obtained by multiplying the longitude from the shaft attached point to force acting point by the force perpendicular component:
T = d * Fp
Notice that the perpindicular component is the total force magnitud times the sino of the angle respect the horizontal:
Fp = F*sin(a)
Replacing the values for the force and the angle:
Fp = 33N*sin(π/5) = 33N * 0.011 = 0.363 N
Taking the distance in meters:
T = 0.2m * 0.363 N = 0.063 Nm
Assuming that directly above point A is the water with height 0.6 meters, the pressure at point A is 5,880 Pascals, neglecting atmospheric pressure above the tank. This can be solved using the density of water, gravitational constant, and height of the water. This is because pressure is dependent on height and type of material. The calculations are as follows:
Pressure = density(gravitational constant)(height)
Pressure = 1000 kg/m^3 (9.8 m/s^2)(0.6m)
Pressure = 5,880 Pascals
