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Bezzdna [24]
3 years ago
12

Salt is now added to the water in the bucket, increasing the density of the liquid. what happens to the tension in the string ?

Physics
1 answer:
AlexFokin [52]3 years ago
5 0

The question involves a ping-pong ball that is held submerged in a bucket by a string attached to the bottom of the bucket.

The answer is the tension of the string will increase. This is because making the water salty increases its density, and consequently, increases its buoyancy. This is why sea water is more buoyant than fresh water. Therefore the ping pong is pushed more upwards by the water when salt is added than initially. This gives the string more tension.


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The simulation shows a game of tug-of-war. Place a blue team and a red team with same-sized people on each side of the rope. Wha
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When same-sized team members are placed on each side of the rope, the sizes of the arrows on both sides remain the same.

Explanation:

This is the answer on Plato

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Explanation:

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The forces on a car are balanced.state and explain the resultant force on the car
Vanyuwa [196]

there will no resultant force

Explanation:

this is because if the forces are balanced on opposite direction. then they cancel each other out

5 newton's ---------> <--------- 5 newton's

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I hope you understand,

5 0
3 years ago
An empty plate capacitor is connected between the terminals ofa 9.0 V battery and charged up. The capacitor is then disconnected
777dan777 [17]

Answer:

The new voltage between the parallel plates of the capacitor is 18V, because for a constant electric field, doubling the space between the parallel capacitor plates, will also double the potential difference (voltage) between the plates.

Explanation:

ΔV = E*Δd

Where;

ΔV is the change in potential difference

Δd is the change in the distance between the parallel plates

E is the electric field potential.

Assuming a constant electric field; E = \frac{v}{d} , then; \frac{v_1}{d_1} =\frac{v_2}{d_2}

when the spacing between the capacitor plates is doubled, d₂ = 2d₁

v₂ = (v₁*d₂)/(d₁)

v₂ = (v₁*2d₁)/(d₁)

v₂ = 2v₁

v₂  = 2(9) = 18 V

Therefore, for a constant electric field, doubling the space between the parallel capacitor plates, will also double the potential difference (voltage).

5 0
3 years ago
The magnetic field strength at the north pole of a 2.0-cmcm-diameter, 8-cmcm-long Alnico magnet is 0.10 TT. To produce the same
hoa [83]

Given Information:  

Current = I = 2.5 A  

Magnetic field = B = 0.10 T  

Radius = r = d/2 = 0.02/2 = 0.01 m

Length = L = 8 cm = 0.08 m

Required Information:  

Number of turns = N = ?  

Answer:  

Number of turns = N ≈ 2547 turns

Step-by-step explanation:  

The approximate model to find the number of turns is given by

B = μ₀nI

Where n = N/L

so

B = μ₀NI/L

N = BL/μ₀I  

Where B is the magnetic field, L is the length of the solenoid, I is the current and μ₀ is the permeability of free space

N = (0.10*0.08)/(4πx10⁻⁷*2.5)

N ≈ 2547 Turns

6 0
3 years ago
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