Question

Can u guys PLEASE answer this question ASAP.

Answer 1

Answer:

n

Step-by-step explanation:

Answer 2

Answer:

$\fbox{\begin{minipage}{11em}N is closer to P than M\end{minipage}}$

Step-by-step explanation:

Step 1: Define the way to calculate distance between 2 points in two-dimensional (2D) plane

Supposing that there are two points $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ on 2D plane.

The distance $d$ between these two points is calculated by:

$d = \sqrt{(x_{1} - x_{2}) ^{2} + (y_{1} - y_{2})^{2} }$

Step 2: Calculate the distance $d_{1}$ between $M(3, 6)$ & $P(-2, -1)$ and distance $d_{2}$ between $N(6, -4)$ and $P(-2, -1)$

Applying the formula in step 1:

$d_{1} = \sqrt{(3+ 2) ^{2} + (6 + 1)^{2} } = \sqrt{25 + 49} = \sqrt{74}$

$d_{2} = \sqrt{(6+ 2) ^{2} + (-4 + 1)^{2} } = \sqrt{64 + 9} = \sqrt{73}$

Step 3: Compare and conclude

Because $\sqrt{73} < \sqrt{74}$  =>  $d_{2} < d_{1}$ => N is closer to P than M

Hope this helps!

:)