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geniusboy [140]
3 years ago
6

Whysudushysususuajsbzgstsysyzyxyzyzusushshshshhshshshshshshshshdhdususududu

Mathematics
1 answer:
Elden [556K]3 years ago
5 0

Answer:

b) -6

Step-by-step explanation:

2\sqrt{10+n}  = 4

Divide both sides by 2

\sqrt{10+n} = 2

Square both sides of the equation

10+n=4

Isolate the variable

n = 4 - 10

4 -10 = - 6

n = - 6

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A flashlight and battery sell together for $9. If the flashlight costs $5 more than the battery, what is the price of each item?
MatroZZZ [7]
The flashlight cost 7 dollars and the batter is 2 dollars
7 0
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Planes Q and R intersect. Lines d and c are vertical on plane R and form a right angle with line B on plane Q. Line B is horizon
Akimi4 [234]

Answer:

C. line d

Step-by-step explanation:

Two parallel lines are lines that do not meet even with continuous extension of their length. While two lines are perpendicular when they form a right angle to each other at the point where they meet.

In the given question, the only figure that would be parallel to line c is line d. Line a is not parallel to line c (since it is slightly diagonal, it would intersect line c at a point) and line B is perpendicular to line c (since it is horizontal to plane Q), same as plane Q. So that lines c and d are parallel to each other.

4 0
3 years ago
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A right rectangular prism has a length of 9, a width of 4, and a height of 5. How many unit cubes can fit in the prism?
Serjik [45]

Answer:

The answer is 54 cubes.

Step-by-step explanation:

5 0
3 years ago
Y=x+1 and y=-x-3 in graphing,Substitution,and elemination
marysya [2.9K]

\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right\\\\GRAPHING\ \text{(look at the picture)}\\\\y=x+1\\for\ x=0\to y=0+1=0\to(0,\ 1)\\for\ x=-1\to y=-1+1=0\to(-1,\ 0)\\\\y=-x-3\\for\ x=0\to y=-0-3=-3\to(0,\ -3)\\for\ x=-3\to y=-(-3)-3=0\to(-3,\ 0)\\\\Solution:\ (-2,\ -1)


SUBSTITUTION\\\\\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right\\\\\text{substitute}\ y=-x-3\ \text{to the first equation}\\\\-x-3=x+1\ \ \ \ |+3\\-x=x+4\ \ \ \ |-x\\-2x=4\ \ \ \ |:(-2)\\x=-2\\\\\text{substitute the value of x to the second equation}\\\\y=-(-2)-3=2-3=-1\\\\Solution:\ (-2,\ -1)


ELIMINATION\\\\\underline{+\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right}\ \ \ |\text{add both sides of the equations}\\.\ \ \ \ 2y=-2\ \ \ \ |:2\\.\ \ \ \ \ \ y=-1\\\\\text{put the value of y to the first equation}\\\\-1=x+1\ \ \ \ |-1\\x=-2\\\\Solution:\ (-2,\ -1)

5 0
3 years ago
Find the distance between (-2,7) and (3, -3). Round to the nearest tenth. Geometry please help
yan [13]

Answer:

15

Step-by-step explanation:

The formula for distance when given vertices is

√(x2 - x1)² + (y2- y1)²

Where we have points (x1,y1) and (x2,y2)

So, (-2,7) and (3, -3)

Distance = √(3 -(-2))² + (-3 -7)²

= √5² + (-10)²

= √25 + 100

= √125

= 15

Therefore, the distance between (-2,7) and (3, -3) is 15

8 0
3 years ago
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