Question

Is the line through points P(7, 6) and Q(9, 11) perpendicular to the line through points R(5, 9) and S(7, 4)? Explain.

Answer 1

Answer:

Step-by-step explanation:

$slope~of~line~PQ=\frac{11-6}{9-7}=\frac{5}{2}\\slope~of~line~RS,~m2=\frac{4-9}{7-5}=-\frac{5}{2} \\m1 \times m2=\frac{5}{2} \times -\frac{5}{2} =-\frac{25}{4} \neq -1$

so lines are not perpendicular.