13 vehicles (at least) will be needed to transport the students. 18x3= 54+10= 64\5= 12.8. Round 12.8 to the nearest while number is 13
12.50 x 2= 25
25+15.99= 40.99
40.99 x 7.5%= 3.07
40.99+3.07= 44.06
Answer is $44.06
Answer:
no
Step-by-step explanation:
1 is obtuse one is acute
Since p^2=p*p,
(p*p)^5 = p*p * p*p * p*p * p*p * p*p = p^10
Answer: D
<u>Step-by-step explanation:</u>
x - 2 = 0 --> x = 2
Using synthetic division:
2 | 4 -5 3 -1
|<u> ↓ 8 6 18</u>
4 3 9 17 ← this is the remainder!
Using remainder theorem:
f(x) = 4x³ - 5x² + 3x - 1
f(2) = 4(2)³ - 5(2)² + 3(2) - 1
= 32 - 20 + 6 - 1
= 17
