Assuming that your question is (x-1)(x+2) = [5(x-1)]/x-1
On the right side, the x-1's will cancel out, leaving you with (x-1)(x+2) = 5
expand the left side, giving you x^2 + x -2 = 5
which goes to x^2 +x -7 = 0
the possible values for x are 2.93 and -3.93. I don't think this was your question, so I'll do the other possible question that you might have been asking.
(x-1)(x+2) = 5(x-1)
divide by x-1 on both sides, leaving you with x+2=5
x+2=5
x=5-3
x=3
Answer: primeter is 20
Area :
Step-by-step explanation:
Height : 4
Base : 6
Prim - 6+6+4+4=20
Area - 6x4=24
1.50s + 0.75f = 116.25
2f = s
1.50(2f) + 0.75f = 116.25
3f + 0.75f = 116.25
3.75f = 116.25
f = 116.25/3.75
f = 31...31 friday papers
2f = s
2(31) = s
62 = s <=== 62 sunday papers
Answer:
if you flipped one of the figures you will see that they are both the same shape and the same distance from the x and y axes.
The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively
<h3>How to find a sector area, and arc length?</h3>
For a sector that has a central angle of θ, and a radius of r;
The sector area, and the arc length are:
--- sector area
---- arc length
<h3>How to find the given sector area, and arc length?</h3>
Here, the given parameters are:
Central angle, θ = 160
Radius, r = 5 inches
The sector area is
So, we have:
Evaluate
A = 34.92
The arc length is:
So, we have:
L = 13.97
Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively
Read more about sector area and arc length at:
brainly.com/question/2005046
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