Answer:
1.) No ;
2.) - 0.931
3.) 0.1785
Step-by-step explanation:
Given :
μ = 84.3 ; xbar = 81.9 ; s = 17.3
H0 : μ = 84.3
H1 : μ < 84.3
The test statistic :
(xbar - μ) ÷ (s/√(n))
(81.9 - 84.3) / (17.3/√45)
-2.4 / 2.5789317
= - 0.9306
= - 0.931
Using the test statistic, we could obtain the Pvalue : df = n - 1 ; df = 45 - 1 = 44
Using the Pvalue calculator :
Pvalue(-0.9306, 44) = 0.1785
Using α = 0.05
The Pvalue > α
Then we fail to reject H0; and conclude that there is no significant evidence to support the claim that the mean waiting time is less than 84.3
Answer:
(4, -2)
Step-by-step explanation:
Given a point R (-2,5), if the point R' is described by a translation of 6 units to the rights and 7 units down, then the coordinate of R' will be;
6 units to the rights is towards the positive x axis
7 units down is towards the negative y axis
R' = (-2+6, 5-7)
R' = (4, -2)
Hence the coordinate point of R' on the plane is (4, -2)
This is exactly like the one with the 'n's that you posted yesterday.
I guess you didn't get enough help on that one to understand it.
<span><u>7k/8 - 3/4 - 5k/16 = 3/8</u>
3/4 is the same as 6/8.
Add it to each side of the equation:
7k/8 - 5k/16 = 9/8
Multiply each side by 16 :
14k - 5k = 18
Add up the 'k's on the left side:
9k = 18
From this point, you can proceed directly to the numerical value of 'k'
if you need it.<u />
In your question, you said you need help, and I showed you how to
strip the problem down so that the only thing left is ' k = something '.
Giving you the answer is no help. Nobody actually needs the answer.
</span>
Answer:
the roots are {-4/3, 4/3}
Step-by-step explanation:
Begin the solution of 11=6|-2z| -5 by adding 5 to both sides:
11=6|-2z| -5 becomes 16 = 6|-2z|.
Dividing both sides by 12 yields
16/12 = |-z|
There are two cases here: first, that one in which z is positive and second the one in which z is negative.
If z is positive, 4/3 = -z, and so z = -4/3, and:
If z is negative, 4/3 = z
Thus the roots are {-4/3, 4/3}
Well i have to say is that PEMDAS exponents first. Hope this helps.
