1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dmitriy789 [7]
3 years ago
6

If the Durbin-Watson statistic is greater than (4 − dL), then we conclude that

Mathematics
1 answer:
solmaris [256]3 years ago
6 0

Answer:

Option(b) is the correct answer to the given question

Step-by-step explanation:

1) If d\leq  dl  then , there must be a positive Autocorrelation

According to it if the ratio d of durbin-watson is equal to or less than dL then it is called as Positive Autocorrelation.

2 ) if , then  it is  Inconclusive

According to it If the coefficient d of the Durbin-Watson is between dL & du then it is called as  Inconclusive.

3) if d\geq  du  then there is No proof of the Autocorrelation

According to it if the d  of the durbin-watson will be less than or equivalent to du then it is called as  No Autocorrelation.

4) If d \leq (4-du) ) then there is No proof of the Autocorrelation

According to it if the d  of the durbin-watson will be less than or equivalent to 4- du then it is called as  No Autocorrelation.

5) If the ( 4 - du ) \leq  d \leq ( 4 -dl )  , then it is Inconclusive

According to it if the  d of the durbin-watson is between the (4-du) \ and \ (4-dl) then it is called as Inconclusive.

6) If the d \geq (4-dl) then it called as  negative Autocorrelation

According to it if the d of the durbin-watson is greater then 4-dl then it is called as negative autocorrelation.

  • From the point 6 we can say that the option(B) is correct
  • All the others options are not correct for (4 − dL), so these are incorrect option .
You might be interested in
Please help, I am really bad at algebra
Marianna [84]
The answer is (0,3)

Hope this helps you
6 0
4 years ago
Read 2 more answers
Factorise fully x^3-x
MA_775_DIABLO [31]

Answer:

x(x+1)(x-1)

Step-by-step explanation:

We see that the two terms share an x, so we can pull that out:

x^3-x=x(x^2-1)

Now notice that we have a difference of squares (x^2-1). Given a difference of squares, a^2-b^2, this can always be factored into (a+b)(a-b). We can use this in this case: x^2-1=(x+1)(x-1).

So, our final factorized form is: x(x+1)(x-1).

Hope this helps!

3 0
3 years ago
the amount of money spent weekly on cleaning maintenance and repairs at a large restaurant was observed over a long period of ti
miv72 [106K]

So P(-0.7537 < z < 1.3190) = 0.9063 - 0.2254 = 0.6809

4 0
3 years ago
Find the product: 9|-5|
lions [1.4K]

Answer:

45

Step-by-step explanation:

The absolute value of negative 5 is 5 because it is five units away from zero, and then 9x5=45.

3 0
3 years ago
Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data
tresset_1 [31]

Based on the information represented by the boxplot ;

  • Latasha's lowest sale amount = 50

  • Kayla's median is between 200 and 300

  • Latasha has a greater spread due to higher IQR value

1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>

  • The minimum value is denoted by the starting position of the lower whisker on a boxplot.

  • Lowest amount of sale made by Latasha = 50

2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>

  • 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

  • 50% of sales made by Kayla is between 200 and 300

  • With median sale value being 250

3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>

  • The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

  • IQR = Upper Quartile (Q3) - Lower quartile(Q1)

<u>For Latasha</u> :

  • Q3 = 450 (Endpoint of the box)
  • Q1 = 150 (starting point of the box)

  • IQR = 450 - 150 = 300

<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>

  • Q3 = 375 (Endpoint of the box)
  • Q1 = 100 (starting point of the box)
  • IQR = 375 - 100 = 275

  • Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

4 0
2 years ago
Other questions:
  • Rename 2934 as tens and ones
    11·1 answer
  • How Do You Write The Expression For Triple 9 Then Multiply 8
    13·1 answer
  • What is the slope of the line with the equation <br> −1x + 3y = 6
    12·1 answer
  • If y equals -18 when x is 6 find x when y is 6
    14·1 answer
  • PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B
    12·2 answers
  • HELP ME ASAP PLEASEEEEEEEE
    13·2 answers
  • If \triangle △RST is isosceles. find x then find m∠S.
    11·2 answers
  • a stock has a price of $58.63. This is $5.92 less than the price of stock yesterday. Write and solve an equation to find the pri
    13·1 answer
  • PLEASE HELP ASAP !!!!!!!!!!!!!!!!!!!
    7·1 answer
  • A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!