Question

X^{2m+n} * x^{n-m} / x^{m+2n}

Answer 1

Answer:

$\boxed{1}$

Step-by-step explanation:

$x^{2m+n} * x^{n-m} / x^{m+2n}$

When bases are same for exponents in division, subtract exponents.

$x^{2m+n} * x^{n-m-(m+2n)}$

$x^{2m+n} * x^{n-m-m-2n}$

$x^{2m+n} * x^{-n-2m}$

When bases are same for exponents in multiplication, add exponents.

$x^{2m+n+-n-2m}$

$x^{2m+0-2m}$

$x^0$

Any base with power or exponent of 0 is 1.

$x^{0}=1$

Answer 2

Answer:

=x

Step-by-step explanation: