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3 years ago

X^{2m+n} * x^{n-m} / x^{m+2n}

Mathematics

2 answers:

Alik [6]3 years ago

7 0

Answer:

$\boxed{1}$

Step-by-step explanation:

$x^{2m+n} * x^{n-m} / x^{m+2n}$

When bases are same for exponents in division, subtract exponents.

$x^{2m+n} * x^{n-m-(m+2n)}$

$x^{2m+n} * x^{n-m-m-2n}$

$x^{2m+n} * x^{-n-2m}$

When bases are same for exponents in multiplication, add exponents.

$x^{2m+n+-n-2m}$

$x^{2m+0-2m}$

$x^0$

Any base with power or exponent of 0 is 1.

$x^{0}=1$

notka56 [123]3 years ago

3 0

Answer:

Step-by-step explanation:

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Step-by-step explanation:

Let the number of years passed since 2010 to reach population more than 7000000 be 'x'.

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$\log(P)=\log(P_0(1+r)^x)\\\log P=\log P_0+x\log (1+r)\\x\log (1+r)=\log P-\log P_0\\x\log(1+r)=\log(\frac{P}{P_0})\\x=\frac{\log(\frac{P}{P_0})}{\log(1+r)}$

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Answer:

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Step-by-step explanation:

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