X^{2m+n} * x^{n-m} / x^{m+2n}

Mathematics

2 answers:

Alik [6]4 years ago

7 0

Answer:

$\boxed{1}$

Step-by-step explanation:

$x^{2m+n} * x^{n-m} / x^{m+2n}$

When bases are same for exponents in division, subtract exponents.

$x^{2m+n} * x^{n-m-(m+2n)}$

$x^{2m+n} * x^{n-m-m-2n}$

$x^{2m+n} * x^{-n-2m}$

When bases are same for exponents in multiplication, add exponents.

$x^{2m+n+-n-2m}$

$x^{2m+0-2m}$

$x^0$

Any base with power or exponent of 0 is 1.

$x^{0}=1$

notka56 [123]4 years ago

3 0

Answer:

Step-by-step explanation:

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