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2 years ago

You roll a fair number cube Find each probability

Mathematics

1 answer:

lara31 [8.8K]2 years ago

5 0

Answer:

The answer is

1. 1/36

2. 1/36

3. 1/12

Step-by-step explanation:

The question is incomplete.

Here is a complete description You roll a fair number cube Find each probability

1. P(3, then 5)

2. P(2 then 2)

3. P(4then odd)

Given the sample space for a die

S=(1, 2,3,4,5,6) = 6

1. probability of 3, then 5= (1/6)*(1/6)

= 1/36

2. Probability of 2 then 2 = (1/6)*(1/6)

= 1/36

3. Probability of 4 then odd,

List of odd numbers = (1,3,5)

1/6* 3/6= 1/6*1/2 = 1/12

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In the United States, the mean and standard deviation of adult men's heights are 70 inches (5 feet 10 inches) and 4 inches, resp

Artyom0805 [142]

Answer:

$P(X>72)=P(\frac{X-\mu}{\sigma}>\frac{72-\mu}{\sigma})=P(Z>\frac{72-70}{4})=P(z>0.5)$

And we can find this probability using the complement rule and the normal standard table:

$P(z>0.5)=1-P(z$

And the best solution would be:

c. 0.3085

Step-by-step explanation:

For this case we can convert all the values to inches in order to standardize the solution:

$5ft * \frac{12 in}{1ft}= 60 in$

$6ft * \frac{12 in}{1ft}= 72 in$

Let X the random variable that represent the heights of US mens, and for this case we know the distribution for X is given by:

$X \sim N(70,4)$

Where $\mu=70$ and $\sigma=4$

We are interested on this probability

$P(X>72)$

We can use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

Using this formula we got:

$P(X>72)=P(\frac{X-\mu}{\sigma}>\frac{72-\mu}{\sigma})=P(Z>\frac{72-70}{4})=P(z>0.5)$

And we can find this probability using the complement rule and the normal standard table:

$P(z>0.5)=1-P(z$

And the best solution would be:

c. 0.3085

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Serggg [28]

0.01.
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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