Someone help please

What is the measure of the missing angle?

Since a triangles total angle is 180°, to find the answer you would subtract the 2 angles you are given from 180. 180-56-36= 88°, this being your answer.

8 0

3 years ago

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How many rectangles can u make with 20 cubes

Mademuasel [1]

<span>"How many rectangles can u make with 20 cubes"
The answer is 4</span>

4 0

2 years ago

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A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.

mezya [45]

1. Divide wire b in parts x and b-x.

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= $\frac{1}{2}sin60^{o}side*side= \frac{1}{2} \frac{ \sqrt{3} }{2} (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}$
A= $\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2} )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}$

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

$2 \pi r=x$

so $r= \frac{x}{2 \pi }$

Area of circle = $\pi r^{2}= \pi ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2} }* x^{2} = \frac{1}{4 \pi } x^{2}$

4. Let f(x)= $\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}$

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)= $\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x$ =0

$\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0$

$(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b$

$x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

6. So one part is $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$ and the other part is b- $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

4 0

2 years ago

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Find three consecutive odd integers such that the sum of the 1st and 2nd number is 344

olga2289 [7]

Answer:

three consecutive odd integers are.

$171, 173, 175$

Step-by-step explanation:

Let x be the first term of odd integer,

Therefore, the second consecutive odd integers = $x+2$

Similarly, the third consecutive odd integers = $x+4$

Given:

The sum of the first term and second term is 344.

first term + second term = 344

Here first term is x and second term is $x+2$ .

$x+(x+2)=344$

$2x+2=344$

$2x=344-2$

$x=\frac{342}{2}$

$x=171$

Therefore, the first odd integers is 171.

And the second consecutive odd integers = $x+2=171+2=173$

Similarly, the third consecutive odd integers = $x+4=171+4=175$

8 0

2 years ago

How is a calculation of net worth different from a day-to-day or month-to-month tallying of expenses?

alina1380 [7]

The difference in tallying of expenses from a day to day and month to month is the consistency. in a day to day basis it is consistent the time for a day is 24 hrs it will not change, so you will really know why the expenses goes up or down/ unlike for a month to month it is inconsistent,, some months have 30, 31 or 28 days in a month.

8 0

2 years ago