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2 years ago

6

HELP PLS ASP WITH THE CORRECT ANSWER I WILL GUVE YOU 17 POINTS PLS ASP!!!! Drag and drop the angles pairs to correctly match the

ir description

1 answer:

Tems11 [23]2 years ago

6 0

COB and COD complementary
AOB and BOC adjacent angle that is neither comp. or supp.
AOC and COD supplementary
AOE and COD vertical

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What is the best estimate for the product of 279 and 7

shutvik [7]

Answer:

279 × 7 ≈ 2800

Step-by-step explanation:

if you have to round to the tens place, then both would be rounded up, the 7 to 10 and the 279 to 280. 10 × 280 = 2800

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2 years ago

Please help. I dont really understand this, you can even just explain it to me and Ill give you brainliest and 30 points :)

polet [3.4K]

When any shape is inscribed in a circle, it means that the shape is within the circle but all of the corners are touching the circle. So this could just look like a square within a circle with the corners of the square touching the circle but not going outside of the borders of the circle. Repeat this process with the other shapes. The central angle used to locate the vertices is found by taking the number of sides on the shape and divide it by 360 (the angle of a circle). So for a square with 4 sides, you would take 360/4 and get 90 degrees. This means that each angle within the square is 90 degrees. That 90 degrees is the interior angle of the polygon (for a square specifically). Then what you do is look at the circle and draw a dot at the center of it. You can use a protractor for this part if you want but you would find the central angle by picking a point on the circle and drawing a line to the center dot, then you rotate however many degrees you found in the interior angle of the polygon and you would draw a new line from the center of the circle to that point. You will continue this process until you have gone back to your starting point on the circle. The amount of times it takes you to repeat the process should be the amount of sides the polygon has that you are trying. Interior angle and central angle should be the same for the individual shapes but it would be different for different shapes like a square and an octagon because there are a different amount of sides.

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2 years ago

A student earns an 80% on their science test. If she got 20 questions correct, how many total were on the test?

galina1969 [7]

25 questions
Explanation: 20 divided by 25 is .8 which is 80%

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2 years ago

What is the BEST deal on sugar?

Lana71 [14]

Answer:

C

Step-by-step explanation:

well if you multiply each of tjem you would only sabe money on c the other choices would cause you to lose money so its c

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3 years ago

If the sum of the even integers between 1 and k, inclusive, is equal to 2k, what is the value of k?

Alisiya [41]

If $k$ is odd, then

$\displaystyle\sum_{n=1}^{\lfloor k/2\rfloor}2n=2\dfrac{\left\lfloor\frac k2\right\rfloor\left(\left\lfloor\frac k2\right\rfloor+1\right)}2=\left\lfloor\dfrac k2\right\rfloor^2+\left\lfloor\dfrac k2\right\rfloor$

while if $k$ is even, then the sum would be

$\displaystyle\sum_{n=1}^{k/2}2n=2\dfrac{\frac k2\left(\frac k2+1\right)}2=\dfrac{k^2+2k}4$

The latter case is easier to solve:

$\dfrac{k^2+2k}4=2k\implies k^2-6k=k(k-6)=0$

which means $k=6$ .

In the odd case, instead of considering the above equation we can consider the partial sums. If $k$ is odd, then the sum of the even integers between 1 and $k$ would be

$S=2+4+6+\cdots+(k-5)+(k-3)+(k-1)$

Now consider the partial sum up to the second-to-last term,

$S^*=2+4+6+\cdots+(k-5)+(k-3)$

Subtracting this from the previous partial sum, we have

$S-S^*=k-1$

We're given that the sums must add to $2k$ , which means

$S=2k$
$S^*=2(k-2)$

But taking the differences now yields

$S-S^*=2k-2(k-2)=4$

and there is only one $k$ for which $k-1=4$ ; namely, $k=5$ . However, the sum of the even integers between 1 and 5 is $2+4=6$ , whereas $2k=10\neq6$ . So there are no solutions to this over the odd integers.

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2 years ago