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zimovet [89]
3 years ago
6

HELP PLS ASP WITH THE CORRECT ANSWER I WILL GUVE YOU 17 POINTS PLS ASP!!!! Drag and drop the angles pairs to correctly match the

ir description

Mathematics
1 answer:
Tems11 [23]3 years ago
6 0
COB and COD complementary
AOB and BOC adjacent angle that is neither comp. or supp.
AOC and COD supplementary
AOE and COD vertical
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You pay $2 to play a game in which you roll one fair die. If you roll a 5 on the first roll, you win $5. If you roll a 1 or a 2,
Kazeer [188]

Answer:

The answer is 4

Step-by-step explanation:

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3 years ago
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Verify sin^4x − sin^2x = cos^4x − cos^2x is an identity
Inga [223]

Answer:

<h2>It's an identity</h2>

Step-by-step explanation:

\sin^4x-\sin^2x=\cos^4x-\cos^2x\\\\L_s=\sin^4x-\sin^2x=\sin^2x(\sin^2x-1)=\sin^2x(-\cos^2x)=-\sin^2x\cos^2x\\\\R_s=\cos^4x-\cos^2x=\cos^2x(\cos^2x-1)=\cos^2x(-\sin^2x)=-\sin^2x\cos^2x\\\\L_s=R_s\qquad\bold{CORRECT}

\text{Used:}\\\\\sin^2x+\cos^2x=1\Rightarrow\left\{\begin{array}{ccc}\cos^2x=1-\sin^2x\\\sin^2x=1-\cos^2x\end{array}\right\Rightarrow\left\{\begin{array}{ccc}-\cos^2x=\sin^2x-1\\-\sin^2x=\cos^2x-1\end{array}\right

4 0
3 years ago
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Find the solution for the system of linear equations by graphing: y=x <br> Y=2x -4
Arte-miy333 [17]

Answer:

x and y = 4

Step-by-step explanation:

Since y=x --->         x=2x-4

                              -x  -x

0=x-4            

+4   +4  ------------------> Therefore, x= 4 and y= y

If you could graph both lines you would find they intersect at (4,4)

6 0
3 years ago
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Find the area of sector JKL. Enter your answer in terms of a fraction of π and rounded to the nearest hundredth.
Anna007 [38]

<u>Given</u>:

The radius of the circle is 4 cm.

The angle of the sector JKL is 135°

We need to determine the area of the sector JKL

<u>Area of the sector:</u>

The area of the sector can be determined using the formula,

A=\frac{\theta}{360^{\circ}} \times \pi r^{2}

Substituting \theta=135^{\circ} , r=4, we get;

A=\frac{135^{\circ}}{360^{\circ}} \times (3.14) (4)^{2}

A=\frac{3}{8} \times (3.14) (16)

A=\frac{150.72}{8}

A=18.84 \ cm^2

Thus, the area of the sector is 18.84 cm²

5 0
4 years ago
How do you factor 16-2m^2?
Free_Kalibri [48]
-(2m^{2} - 16)
-2(m^{2} - 8)
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Hope this helps!
4 0
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