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Leviafan [203]
3 years ago
15

Convert 6 20 into a decimal

Mathematics
1 answer:
lakkis [162]3 years ago
6 0

Answer:

6.20

wait what do u mean

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A line is drawn through (-7, 11) and (8.-9). The equation
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Answer:

this answer has to be A because the libra of the pole goes west

Step-by-step explanation:

this answer has to be A because the libra of the pole goes west

8 0
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PLEASE ANSWER!! is it a, b, c or d!?
denis-greek [22]

Answer:

<h3>C. </h3>

Step-by-step explanation:

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4 0
3 years ago
Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1
defon
I'm guessing the series is supposed to be

\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}

By the ratio test, the series converges if the following limit is less than 1.

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|

The first n terms in the numerator's denominator cancel with the denominator's denominator:

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|

|x^n| also cancels out and the remaining factor of |x| can be pulled out of the limit (as it doesn't depend on n).

\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0

which means the series converges everywhere (independently of x), and so the radius of convergence is infinite.
3 0
3 years ago
A spool of rope contains 79 yards of rope. How many​ 4-foot pieces of rope can be cut from the​ spool? How much rope is left​ ov
mart [117]
<h2>Answer:</h2>

59 can be cut from the spool.

3 Inches is left over.

<h2>Step-by-step explanation:</h2>
  1. 237 feet in 79 yards.
  2. 237 / 4 = 59.25
  3. 59 is the whole number, .25 is what is left over.
  4. .25 feet is 3 inches.

8 0
3 years ago
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If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen
Svetllana [295]
Hello,

\left \{ {{3x+2y=-21} \atop {x-3y=4}} \right. \\\\&#10; \left \{ {{3x+2y=-21} \atop {x=4+3y}} \right. \\\\&#10; \left \{ {{3(4+3y)+2y=-21} \atop {x=4+3y}} \right. \\\\&#10;&#10; \left \{ {{12+9y+2y=-21} \atop {x=4+3y}} \right. \\\\&#10; \left \{ {{12+11y=-21} \atop {x=4+3y}} \right. \\\\&#10; \left \{ {{11y=-21-12} \atop {x=4+3y}} \right. \\\\&#10; \left \{ {{11y=-33} \atop {x=4+3y}} \right. \\\\&#10; \left \{ {{y=-3} \atop {x=4+3(-3)}} \right. \\\\&#10; \left \{ {{y=-3} \atop {x=5}} \right. \\\\&#10;Sol=\{(5,-3)\}\\\\&#10;&#10;&#10;&#10;
3 0
3 years ago
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