2 years ago

Find the missing angles and sides

Mathematics

1 answer:

maria [59]2 years ago

8 0

Step-by-step explanation:

m∠1 = 180-100 = 80

m∠2 = 180-150 = 30

m∠3 = 180-(80+30) = 180 - 110 = 70

using the law of sine :

AC/sin(m∠2) = 5/sin(m∠3) ⇒ AC = sin(m∠2)*(5/sin(m∠3)) = sin(30)×(5÷sin(70))

=2.66044443119

CB/sin(m∠1) = 5/sin(m∠3) ⇒ CB = sin(m∠1)*(5/sin(m∠3)) ⇒ CB = sin(80)×(5÷sin(70)) = 5.240052604588

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