Answer:
the answer is A just tool the quiz lesson 5 hyperbolas Algebra 2B unit 5 these are the correct answers
1.A
2.B
3.D
4.A
5.B
6.D
7.A
hopes this helps everyone
Answer:
The volume of the concentrated 80 gallons mixture is 20 gallons
The volume of water in the 80 gallons mixture is 60 gallons
Step-by-step explanation:
The given parameters are;
The content of Container A = The cleaner
The concentration of the cleaner = 20% solution
The content of Container B = Pure water
The concentration of the desired solution = 5%
The volume of the required solution = 80 gallons
Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture
Therefore, we have;
20/100 × x + y×0 = 5/100×80
x + y = 80
y = 80 - x
20/100 × x + (80 - x)×0 = 5/100×80
0.2·x = 4
x = 4/0.2 = 20
x = 20 gallons
y = 80 - x = 80 - 20 = 60
y = 60 gallons
The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons
The volume of water in the 80 gallons mixture = y = 60 gallons.
Rachel would take 30 minutes to run in 4miles
Answer:
y = 0.2x + 37
Step-by-step explanation:
A) Find an equation in the form y = mx + b, where x is the number of monthly minutes used and y is the total monthly of the Ringular plan.
(x, y) = (minutes, cost)
(110, 59)
(600, 157)
slope = m = dy/dx
dy/dx = change in y/change in x
m = dy/dx
m = (157 - 59)/(600-110)
m = 98/490
m = 0.2
a) the linear equation:
y - 59 = 0.2(x - 110)
y - 59 = 0.2x - 22
y = 0.2x - 22 + 59
y = 0.2x + 37
