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Shtirlitz [24]
3 years ago
15

Write the equation of the line that passes through the points (6,2) (4,1)

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
4 0

Answer:

see below

Step-by-step explanation:

slope = 2 - 1 / 6 - 4 =1/2

Point slope formula (I used point (6,2)):

y - 2 = 1/2 (x - 6)

y = 1/2 x - 1

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Solve 3 (b – 4) = 2 (-26+1)<br><br> please show your work.
ozzi

Answer:

Step-by-step explanation:

3(b-4)=2 b=0.6667

=2(-26+1) 2x-27

=-54

-54 is the answer

8 0
3 years ago
Select the perfect square trinomial from among the options below!
charle [14.2K]

A ) ( x - 3 )( x + 1 ) [ not perfect ]

B ) ( x + 5 - √5 )( x + 5 + √5 ) [ n p ]

C ) ( x + 2 + 2√2 )( x + 2 - 2√2 ) [n p ]

D ) ( x - 6 )( x - 6 ) = ( x - 6 )^2 [ perfect ]

Thus the correct answer is option D .

4 0
2 years ago
Read 2 more answers
A)180.48 m2<br><br> B)180.48 m<br><br> C)80.48 m2<br><br> D)80.48 m
MissTica

Answer:

80.48m2

Step-by-step explanation:

I think this is right but it may be wrong.

4 0
2 years ago
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5 0
3 years ago
What is the length of the diameter of a circle inscribed in a right triangle with the length of hypotenuse c and the sum of the
jeyben [28]

Answer:

  diameter = m - c

Step-by-step explanation:

In ΔABC, let ∠C be the right angle. The length of the tangents from point C to the inscribed circle are "r", the radius. Then the lengths of tangents from point A are (b-r), and those from point B have length (a-r).

The sum of the lengths of the tangents from points A and B on side "c" is ...

  (b-r) +(a-r) = c

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Now, the problem statement defines the sum of side lengths as ...

  a+b = m

and, of course, the diameter (d) is 2r, so we can rewrite the above equation as ...

  m -d = c

  m - c = d . . . . add d-c

The diameter of the inscribed circle is the difference between the sum of leg lengths and the hypotenuse.

5 0
3 years ago
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