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Alexxandr [17]
3 years ago
14

Whats is the first step in solving the quadratic equation

Mathematics
1 answer:
zalisa [80]3 years ago
6 0

Answer:

you first need to set up your euqation and make the eqation equal to zero.

Step-by-step explanation:

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What is 93 divided by 7
igomit [66]
7 goes into 9, that's 1.
Remaining 2.

Move the 2 close to 3, you have 23.

7 into the 23, that's 3 times. 3 times 7 is 21.
So you are left with 2.

The answer is 13 remainder 2.

13\2\7
5 0
3 years ago
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Is there a solution to 2x^2+7x-4=0?
IgorLugansk [536]

Answer:

x= -8    x= 1

Step-by-step explanation:

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3 years ago
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. A hotel elevator is on the 14th floor. If it goes up 5 floors, then goes down 8 floors, what floor is it now on?
vampirchik [111]
14+5= 19; 19-8=11. the hotel elevator is now on the 11th floor
4 0
3 years ago
Two number cubes are rolled. What is the probability of rolling a sum of 9 or a sum that is even?
Murljashka [212]

Well I don't know !
Let's figure it out together.

Each cube can land in 6 different ways, so the total number
of possible results with two cubes is (6 x 6) = 36 .

Now we need to figure out how many of those 36 possibilities
meet your specifications ... either 9 or any even number.

Ways to make 9 :

3 . . . 6
6 . . . 3
4 . . . 5
5 . . . 4

Four ways to make 9.
____________________________

Ways to make an even number:

1 . . . 1
3 . . . 1
1 . . . 3
2 . . . 2
5 . . . 1
1 . . . 5
6 . . . 2
2 . . . 6
6 . . . 4
4 . . . 6
6 . . . 6

Eleven ways to make an even number.
_____________________

Total number of ways to succeed = (4 + 11) = 15 ways

So the probability of succeeding (rolling 9 or an even number)
is

               15 / 36  =  5 / 12  =  0.41666... =  (41 and 2/3) % .

8 0
3 years ago
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How do you figure out what numbers are terminating and what numbers are repeating ?
raketka [301]
You can simply look and see if one is terminating by seeing if it ends. For example, 2.54 is terminating since the numbers after the decimal aren't repeating. A repeating number is for example 0.555555..
3 0
2 years ago
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