Answer:
Options A, C, and F
Step-by-step explanation:
Answer:
36
Step-by-step explanation:
2 *3 sqare root 3 * 12
Solving gives:
6 sqare root 36.
sqare root 36 = 6
2 * 6 * 3
So our answer is 36.
Answer:
Margin of error of 0.0485 hours.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 1.96.
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
In this question:

The margin of error is of:



Margin of error of 0.0485 hours.
There are numerous important information's already given in the question. Based on those information's the answer to the question can be easily determined.
Number of movies that are drama = 5
Number of comedy movies = 8
Number of adventure movies = 11
Total number of movies that Jazmin has = 5 + 8 + 11
= 24
Then
Ratio of adventure movies to the total number of movies = 11:24
This ratio of 11:24 cannot be simplified further. So this is the answer to the given question. I hope the procedure is clear enough for you to understand.