Answer:
y=-2/3x-3
Step-by-step explanation:
Answer:
(a) see attached
(b) CD = 29
Step-by-step explanation:
<h3>(a) </h3>
See the attachment for a diagram.
In the diagram, we have shown point E on the plane so that BE is parallel to AC.
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<h3>(b)</h3>
Triangle BDE is a right triangle with hypotenuse BD = 25 and leg BE = AC = 15. The length DE is given by the Pythagorean theorem as ...
DE = √(BD^2 -BE^2) = √(625 -225) = 20
Triangle CDE is a right triangle with hypotenuse CD and legs CE = 21 and DE = 20. The length of the hypotenuse is also given by the Pythagorean theorem as ...
CD = √(CE^2 +DE^2) = √(21^2 +20^2) = √841
CD = 29
(6 - 2) x 180 = 720
720 - 112 - 120 - 100 - 128 - 133
= 127
9514 1404 393
Answer:
(2) 72°
Step-by-step explanation:
In this geometry, the angle at the tangent is half the measure of the intercepted arc.
∠CBD = (arc BD)/2 = 144°/2
∠CBD = 72°
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<em>Additional comment</em>
Consider a point X anywhere on long arc BD. The inscribed angle at X will have half the measure of short arc BD, so will be 144°/2 = 72°. This is true regardless of the position of X on long arc BD. Now, consider that X might be arbitrarily close to point B. The angle at X is still 72°.
As X approaches B, the chord XB approaches a tangent to the circle at B. Effectively, this tangent geometry is a limiting case of inscribed angle geometry.