The volume of the cone is 2880 m3.
The scale factor is 1/4.
The volume of the cone has the formula (1/3)π r² h.
A scale factor of 1/4 will reduce the dimensions by 1/4 which will result to a total volume reduction of (1/4)³ = 1/64
The new volume will be 45 m3
Answer:
glucose, sunlight and oxygen on the left (they go in the cell)
water and carbon dioxide on the right (they go out of the cell)
45 times the numerator plus the denominator is most likely going to equal the same amount as if it were doubled.
Answer:
14x+7y
Step-by-step explanation:
H'(x) = 2f'(x)
h'(1) = 2*f'(1) = 2*4
h'(1) = 8
