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ioda
3 years ago
12

Howard needs new gutters for the front and both sides of his home. The front of the house is 50 ft 8 in., and each side is 22 ft

9 in. Wide. What length of gutter must he buy?
Mathematics
1 answer:
tankabanditka [31]3 years ago
5 0

Answer:

95 ft 10 in

Step-by-step explanation:

We need to add the lengths of the front of the house and both sides of the house:

50 ft 8 in + 2(22ft + 9in)

= 50ft + 8 in + 44ft + 18in

= 94ft + 22in

12 inches = 1 foot

22 inches = 1 ft 10 in

Therefore, the length of the gutter he must buy must be:

94 ft + 1 ft + 10 in

= 95 ft 10 in

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Abby used the law of cosines for TriangleKMN to solve for k.
torisob [31]

Answer:

  m∠K = 37° and n = 31

Step-by-step explanation:

A lot of math is about matching patterns. Here, the two patterns we want to match are different versions of the same Law of Cosines relation:

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  • k² = 31² +53² -2·31·53·cos(37°)

<h3>Comparison</h3>

Comparing the two equations, we note these correspondences:

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Comparing these values to the given information, we see that ...

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Abby apparently knew that ∠K = 37° and n = 31.

__

<em>Additional comment</em>

Side and angle naming for the Law of Sines and the Law of Cosines are as follows. The vertices of the triangle are labeled with single upper-case letters. The side opposite is labeled with the same lower-case letter, or with the two vertices at either end.

Vertex and angle K are opposite side k, also called side NM in this triangle.

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2 years ago
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