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hodyreva [135]
3 years ago
13

Which is a symmetric distribution?

Mathematics
1 answer:
MrRissso [65]3 years ago
5 0

Answer:

100% guarantee its D for A P E X :)

Step-by-step explanation:

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4 years ago
How do you make all of these equation true in the circles you put either addition sign division sign multiplication sign subtrac
love history [14]

Answer:

in steps

Step-by-step explanation:

12 - 6 x 2 + 3 = 3

(12 - 6 ÷ 2) x 3 = 27 .... ??

12 ÷ 6 + 2 x 3 = 8

12 ÷ 6 + 2 + 3 = 7

12 + 6 ÷ 2 + 3 = 18

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3 years ago
`
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Answer:

~~~~~~~~~~~~~~~~~~~~~~~~~.~~~~~~~~~~~~~~~~~~~~~~~~~

Step-by-step explanation:

4 0
3 years ago
4. Why studying central tendency alone is insufficient and calculating dispersion is always needed in both descriptive and infer
ira [324]

Answer:

Check below for the answer and explanation.

Step-by-step explanation:

Studying the central tendency alone is not sufficient because apart from calculating the value of the central point of a group of data ( which is what the measure of central tendency does), it is important to also understand the spread of these data about the average(mean) value.The measure of dispersion will help us to know the range of error that is recorded in both descriptive and inferential statistics and this will enable the statistician to assess the validity of the data generated from the experiment performed.

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4 0
3 years ago
probability that cars have been assembled in a particular plant as follows: P(plant1)=20% , P(plant 2)=24% , P(plant 3.25% , P(p
Bogdan [553]

Answer:

16800/year

Step-by-step explanation:

Plant 1= 20%

Plant 2 = 24%

Plant 3 = 25%

Plant 4 = 31%

Total cars produced 100% = 1,200,000

Number of cars produced in plant 1 =

20% of 1,200,000 = 0.2 x 1,200,000 = 240,000 cars

Number of cars produced in plant 2 =

24% of 1,200,000 = 0.24 x 1,200,000 = 288,000 cars

Number of cars produced in plant 3 =

25% of 1,200,000 = 0.25 x 1,200,000 = 300,000 cars

Number of cars produced in plant 4 =

31% of 1,200,000 = 0.31 x 1,200,000 = 372,000 cars

Number of cars with no warranty claim in plant 1/year 223200

Number of cars with warranty claims in plant 1 + number of cars with no warranty claim in plant 1  = total number of cars produced in plant 1

X + 223200 = 240000  

X = 240000 - 223200

X = 16800/year

number of cars with warranty claim in plant 1/ year is 16800

6 0
3 years ago
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