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LuckyWell [14K]
3 years ago
7

The low temperature for 5 days was -5 degrees, -7 degrees, -2 degrees, 2 degrees, and - 3 degrees. What was the average temperat

ure for those days
Mathematics
1 answer:
weqwewe [10]3 years ago
5 0
The average low is -15 is that what you meant?
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Find the sum of the infinite series, if it exists. 100+20+4+… And please show work
Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

r=20/100=0.2<|1|

S_{\infty} =\frac{a_{1}}{1-r} \\=\frac{100}{1-0.2} =\frac{100}{0.8} =125

4 0
3 years ago
If it takes Mathew an hour to get to his friends house and 2 hours if he drives 25mph slower, how far away does Mathew’s friend
Zinaida [17]

50 mph

1*(S)=2*(S-25)=S=2S-50=0=S-50=S=50

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3 years ago
Find an nth-degree polynomial function with real coefficients satisfying the given conditions. If you are using a graphing utili
Marrrta [24]

We need to find a polynomial function f(x) with degree 3 and zeros 2 and 2i, such that:

f(-1)=30

Since 2i is a zero, -2i is also a zero of this function. Thus, we have:

f(x)=a(x-2)(x-2\imaginaryI)(x+2\imaginaryI)

where a is a constant.

Expanding the expression on the right side, we obtain:

\begin{gathered}  \\ f(x)=a(x-2)\lbrack x²-(2i)²\rbrack \\  \\ f(x)=a(x-2)(x²-4i²),\text{ i^^b2=-1} \\  \\ f(x)=a(x-2)(x²+4) \\  \\ f(x)=a(x³-2x²+4x-8) \end{gathered}

Now, using f(-1) = 30, we obtain:

\begin{gathered} 30=a\lbrack(-1)³-2(-1)²+4(-1)-8\rbrack \\  \\ 30=a(-1-2-4-8) \\  \\ 30=a(-15) \\  \\ a=\frac{30}{-15} \\  \\ a=-2 \end{gathered}

Therefore, the function is:

Answer

f(x)=-2x^{3}+4x^{2}-8x+16

6 0
1 year ago
5. Solve the following inequality –1 + 6(-1 - 3x) &gt; -39 - 2x.
Stells [14]

Answer:

Step-by-step explanation:

7 0
3 years ago
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