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mariarad [96]
2 years ago
5

Solve the following quadratic equation by rearranging and then factorising x^2 + 3x - 15 = 2x - 13

Mathematics
2 answers:
Whitepunk [10]2 years ago
8 0

Answer:

x = -2   & x = 1

Step-by-step explanation:

x^2 + 3x - 15 = 2x - 13 so you takeaway 2x and add 13 to the other side to get x^2 + x - 2 = 0

(x+2)(x-1) = 0 find factors of -2 that get you x

(x+2) = 0 so x = -2       (x-1) = 0  so x = 1

NNADVOKAT [17]2 years ago
7 0

Step-by-step explanation:

x² + 3x - 15 = 2x - 13

x² + x - 2 = 0

(x + 2)(x - 1) = 0

By zero product rule, (x + 2) = 0 or (x - 1) = 0.

Hence x = -2 or x = 1.

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3 years ago
The same Honey is sold in two different size jars. Large jar= 540g for £4.10 Small jar= 360g for £2.81. By considering the amoun
Ray Of Light [21]

Answer:

From our calculations the large jar is the best value for money because a penny buys more honey

Step-by-step explanation:

<h2>In this problem we are expected to determine which purchase of honey is the cheapest ? large jar or small jar ?.</h2><h2 />

We will determine which has the best value for money using the quantity a pound can purchase.  

firstly for the large jar.

if £4.10 will purchase 540g of honey then,

   £1.00 will purchase xg

cross multiplying to find x will have

x=  \frac{1.00*540g}{4.10}

x= 131.7grams

Hence for the large jar a penny would buy 131.7g of honey

secondly for the small jar

if £2.81 will purchase 360g of honey then,

   £1.00 will purchase xg

cross multiplying to find x will have

x=\frac{1.00*360g}{2.81}\\x= 128.1gram

Hence for the small jar a penny would buy 128.1g of honey

4 0
3 years ago
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6 0
2 years ago
Which equation has the solutions x = startfraction 5 plus-or-minus 2 startroot 7 endroot over 3 endfraction?
Shtirlitz [24]

The equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

<h3>How to determine the equation?</h3>

The solution is given as:

x = \frac{5 \pm \sqrt{7}}{3}

The solution to a quadratic equation is

x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

By comparing both equations, we have:

-b = 5

b^2 - 4ac = 7

2a = 3

Solve for b in -b = 5

b = -5

Solve for a in 2a = 3

a = 1.5

Substitute values for a and b in b^2 - 4ac = 7

(-5)^2 - 4 * 1.5c = 7

Evaluate

25 - 6c = 7

Subtract 25 from both sides

-6c = -18

Divide by - 6

c = 3

So, we have:

a = 1.5

b =  -5

c = 3

A quadratic equation is represented as:

ax^2 + bx + c = 0

So, we have:

1.5x^2 - 5x +3 = 0

Multiply through by 2

3x^2 - 10x + 6 = 0

Hence, the equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

Read more about quadratic equation at:

brainly.com/question/1214333

#SPJ1

7 0
1 year ago
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