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mariarad [96]
3 years ago
5

Solve the following quadratic equation by rearranging and then factorising x^2 + 3x - 15 = 2x - 13

Mathematics
2 answers:
Whitepunk [10]3 years ago
8 0

Answer:

x = -2   & x = 1

Step-by-step explanation:

x^2 + 3x - 15 = 2x - 13 so you takeaway 2x and add 13 to the other side to get x^2 + x - 2 = 0

(x+2)(x-1) = 0 find factors of -2 that get you x

(x+2) = 0 so x = -2       (x-1) = 0  so x = 1

NNADVOKAT [17]3 years ago
7 0

Step-by-step explanation:

x² + 3x - 15 = 2x - 13

x² + x - 2 = 0

(x + 2)(x - 1) = 0

By zero product rule, (x + 2) = 0 or (x - 1) = 0.

Hence x = -2 or x = 1.

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0.07

Step-by-step explanation:

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40/100, 90/100, 7/100

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0.4, 0.9, 0.07

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3 years ago
What formula would you use to find the area of a parallelogram?
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b x h

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Z=9x+14xy for x what is x
cluponka [151]
<span>Z=9x+14xy for x what is x

Z = x (9 +14y)

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4 years ago
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AlekseyPX

Answer: <em><u>Reflection</u></em>

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6 0
3 years ago
Not sure if i got this right?
aleksandrvk [35]

Answer:

The effect it will have on the volume is;

The volume will be 8 times larger

Step-by-step explanation:

The dimensions of the given prism are;

The length of the prism, l = 5 in.

The breadth of the prism, b = 5 in.

The slant height of the prism,  = 4 in. by 5 in.

The height of the prism, h = 7 in.

The shape of the prism = Parallelepiped

The volume of a parallelepiped = Area of Base × Height of the prism

The base area of the parallelepiped = The length × Breadth of the parallelepiped

∴ The base area of the given parallelepiped = 5 in. × 5 in. = 25 in.²

The volume of the given parallelepiped, V₁ is found as follows;

V₁ = 5 in. × 5 in. × 7 in. = 25 in.² × 7 in. = 175 in.³

When a scale factor of 2 in applied to the dimensions of the prism, we have;

The new volume, V₂ =  2 × 5 in. × 2 × 5 in. × 2 × 7 in.

∴ V₂ = 2 × 2 × 2 × 5 in. × 5 in. × 7 in. = 8 × 5 in. × 5 in. × 7 in. = 8 × V₁

Therefore;

V₂ = 8 × V₁

The volume of the image of the object, V₂ after applying a scale factor of 2 is 8 times larger than the volume of the object, V₁.

5 0
3 years ago
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