Garrett is 3 years older than Rachael. In 2 years the sum of their ages will be 39. How old is Garrett now?

If 14 out of 20 students are male, what percentage of the class is male

Lelechka [254]

Answer:

14:20, 14/20, 14 to 20, 7:10, 7/10, 7 to 10. And in porcent is 70% : )

3 0

3 years ago

NASA launched another space probe, Voyager 2 on August 20, 1977. Voyager 2 is a bit slower than Voyager 1 only traveling 15.4 km

slava [35]

Using proportions, it is found that it will take Voyager 2 82,900 years from its location to travel to the second closest star.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

In this problem, the Voyager 2 travels 15.4 km/s. In kilometers per year, considering that one hour has 3600 seconds, the measure is given by:

15.4 x 365 x 24 x 3600 = 485,654,400 km/year.

The distance to Proxima Centauri in km is given by:

d = |1.93 x 10^10 km - 4.24 x 9.5 x 10^12 km| = 4.02607 x 10^13 km.

Hence the time in years is given by:

t = d/v = 4.02607 x 10^13/485,654,400 = 82,900.

It will take Voyager 2 82,900 years from its location to travel to the second closest star.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

6 0

2 years ago

How do you do this math 18-0.4<br> in long subtraction

Gwar [14]

18.0 1
- 0.4 17.0
_____ - 0.4
-------> ____
17.6

5 0

3 years ago

Read 2 more answers

A data set with a mean of 34 and a standard deviation of 2.5 is normally distributed

tresset_1 [31]

Answer:

a) $z= \frac{34-34}{2.5}= 0$

$z= \frac{39-34}{2.5}= 2$

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

b) $P(X$

$z= \frac{31.5-34}{2.5}= -1$

So one deviation below the mean we have: (100-68)/2 = 16%

c) $z= \frac{29-34}{2.5}= -2$

$z= \frac{36.5-34}{2.5}= 1$

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

Step-by-step explanation:

For this case we have a random variable with the following parameters:

$X \sim N(\mu = 34, \sigma=2.5)$

From the empirical rule we know that within one deviation from the mean we have 68% of the values, within two deviations we have 95% and within 3 deviations we have 99.7% of the data.

We want to find the following probability:

$P(34 < X$

We can find the number of deviation from the mean with the z score formula:

$z= \frac{X -\mu}{\sigma}$

And replacing we got

$z= \frac{34-34}{2.5}= 0$

$z= \frac{39-34}{2.5}= 2$

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

For the second case:

$P(X$

$z= \frac{31.5-34}{2.5}= -1$

So one deviation below the mean we have: (100-68)/2 = 16%

For the third case:

$P(29 < X$

And replacing we got:

$z= \frac{29-34}{2.5}= -2$

$z= \frac{36.5-34}{2.5}= 1$

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

7 0

3 years ago

5-2 ????=7-5 ???? which value of x is the solution to the above equation?

saw5 [17]

5-2x=7-5x
-2x+5x=7-5
3x=2
X=2/3

8 0

4 years ago