A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9
B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6
C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16
D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25
The answer is D.
Answer:
3
Step-by-step explanation:
Answer:
Perimeter = 317 m
Step-by-step explanation:
Given track is a composite figure having two semicircles and one rectangle.
Perimeter of the given track = Circumference of two semicircles + 2(length of the rectangle)
Circumference of one semicircle = πr [where 'r' = radius of the semicircle]
= 25π
= 25 × 3.14
= 78.5 m
Length of the rectangle = 80 m
Perimeter of the track = 2(78.5) + 2(80)
= 157 + 160
= 317 m
Therefore, perimeter of the track = 317 m
Answer:
A=54m²
Step-by-step explanation:
A = hbb/2 =9 · 12/2 = 54m²
Answer:
B
Step-by-step explanation:
If each input value leads to only one output value, classify the relationship as a function. If any input value leads to two or more outputs do not classify the relationship as a function.
