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3 years ago

A sandbox is 2.5 m wide and 3.4 m long . approximately how much sand will it take to fill it 0.3 m deep?

Mathematics

1 answer:

deff fn [24]3 years ago

6 0

I think that the answer should be around 2.55

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Simplify by combining like terms: -4x - 2y - 7x - 8y

Sav [38]

Step-by-step explanation:

Solving like terms

-4x - 7x - 2y -8y

-11x - 10y

3 0

3 years ago

1 Pound brown sugar is equivalent to _____ cups

iogann1982 [59]

Answer:

3 1/2 or said as 3.5 cups is equal to 1 pound

Step-by-step explanation:

1 Pound brown sugar is equivalent to ___3 1/2 or 3.5 __ cups

Hope This Helped

7 0

1 year ago

Hi can someone please answer this question? Thank you :)

Ksenya-84 [330]

3/2
You go up 3 and to the right 2

6 0

3 years ago

What is the value of f(4) + f(7)

tatyana61 [14]

Is there more to this problem? By saying f(4), you'd be inputting a 4 for every variable x. There is not enough info here to answer the question.

7 0

3 years ago

12. If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95% confident that th

atroni [7]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

Step-by-step explanation:

We have the following info given:

$Confidence= 0.95$ the confidence level desired

$ME =0.03$ represent the margin of error desired

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

The confidence level is 95% or 0.95, the significance is $\alpha=0.05$ and the critical value for this case using the normal standard distribution would be $z_{\alpha/2}=1.96$

Since we don't have prior information we can use $\hat p= 0.5$ as an unbiased estimator

Also we know that $ME =\pm 0.03$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

6 0

3 years ago