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3 years ago

To increase an amount by 7%, what single multiplier would you use ?

Mathematics

2 answers:

Scrat [10]3 years ago

6 0

You would use 1.07 for that

Serjik [45]3 years ago

4 0

To Increase an amount by 7% what single multiplier would you use
We want 7% more than 100% of the amount, so the multiplier is
(100% + 7%) = 107% = 1.07
[Remember that "percent" means "per hundred," so we divide a percentage by 100 to get the numerical equivalent.]

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8 and 11/100 into a mixed number and a decimal

katrin [286]

Answer:

8.11 and 9 1/11

Step-by-step explanation:

7 0

3 years ago

Solve 3x + 2 = 15 for x using the change of base formula log base b of y equals log y over log b. −1.594 0.465 2.406 4.465

disa [49]

Answer:

The value in 3x + 2 = 15 for x using the change of base formula is 0.465 approximately and second option is correct one.

Solution:

Given, expression is $3^{(x+2)}=15$

We have to solve the above expression using change of base formula which is given as

$\log _{b} a=\frac{\log a}{\log b}$

Now, let us first apply logarithm for the given expression.

Then given expression turns into as, $x+2=\log _{3} 15$

By using change of base formula,

$x+2=\frac{\log _{10} 15}{\log _{10} 3}$

x + 2 = 2.4649

x = 2.4649 – 2 = 0.4649

Hence, the value of x is 0.465 approximately and second option is correct one.

3 0

3 years ago

Read 2 more answers

Please help me!

Mandarinka [93]

Answer:

its c

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

General solutions of sin(x-90)+cos(x+270)=-1 {both 90 and 270 are in degrees}

mixer [17]

Answer:

$\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

Step-by-step explanation:

Given:

$\sin (x-90^{\circ})+\cos(x+270^{\circ})=-1$

First, note that

$\sin (x-90^{\circ})=-\cos x\\ \\\cos(x+270^{\circ})=\sin x$

So, the equation is

$-\cos x+\sin x= -1$

Multiply this equation by $\frac{\sqrt{2}}{2}:$

$-\dfrac{\sqrt{2}}{2}\cos x+\dfrac{\sqrt{2}}{2}\sin x= -\dfrac{\sqrt{2}}{2}\\ \\\dfrac{\sqrt{2}}{2}\cos x-\dfrac{\sqrt{2}}{2}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos 45^{\circ}\cos x-\sin 45^{\circ}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos (x+45^{\circ})=\dfrac{\sqrt{2}}{2}$

The general solution is

$x+45^{\circ}=\pm \arccos \left(\dfrac{\sqrt{2}}{2}\right)+2\pi k,\ \ k\in Z\\ \\x+\dfrac{\pi }{4}=\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{4}\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

4 0

3 years ago

Find the missing number. 7 × = 21

dalvyx [7]

Answer:

7x3=21

Step-by-step explanation:

pls mark Brainliest :)

3 0

3 years ago