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Andrews [41]
3 years ago
15

Find the maximum height of the cannon ball (t)= -16t + 128t

Mathematics
1 answer:
Bond [772]3 years ago
5 0

Answer:

t= 0

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain variables.

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Suppose that the weight (in pounds) of an airplane is a linear function of the total amount of fuel (in gallons) in its tahk. Wh
kvasek [131]

Answer:

2002 pounds

Explanation:

To know the weight of the plane, we need to find an equation that relates the amount of fuel to the weight.

This equation can be founded using the following

y-y_1=m(x-x_1)

Where m is the slope, x1 is the number of gallons and y1 is the respective weight. So, replacing m = 6.0, x1 = 51 gallons and y1 = 2206 pounds, we get:

y-2206=6(x-51)

Now, we can solve for y

\begin{gathered} y-2206=6(x)-6(51) \\ y-2206=6x-306 \\ y=6x-306+2206 \\ y=6x+1900 \end{gathered}

Then, we can calculate the weight of an airplane with 17 gallons of fuel replacing x = 17 on the equation above

y = 6x + 1900

y = 6(17) + 1900

y = 102 + 1900

y = 2002

Therefore, the answer is 2002 pounds

5 0
1 year ago
Consider the circle shown with center O and points A , B , C , and D on the circle.
leva [86]

Answer:

the answer is c

Step-by-step explanation:

3 0
2 years ago
George has 28 tomato seedlings. He wants to put them into 7 equal groups to sell. Which number sentence could be used to find th
777dan777 [17]

Answer:

4

Step-by-step explanation:

7+7+7+7 or 28/7 =4

4 0
2 years ago
The slope of a line is 1, and the y-intercept is -1. What is the equation of the line written in slope-intercept form?
Scilla [17]
The slope-intercept form is:
y = mx + b
where m = slope, and b = y-intercept.
You need a slope of 1, so m = 1.
You need a y-intercept of -1, so b = -1.
Replace m with 1 and b with -1 in the slope intercept form to get

y = 1x + (-1)

which simplifies to

y = x - 1
3 0
3 years ago
What is the interquartile range (IQR) of the following data set 17 16 21 15 25 22 18 23 17
Pepsi [2]

IQR = 6

First locate the median Q_{2} at the centre of the data arranged in ascending order. Then locate the lower and upper quartiles Q_{1} and Q_{3} located at the centre of the data to the left and right of the median.

Note that if any of the above are not whole values then they are the average of the values either side of the centre.

rearrange data in ascending order

15 16 ↓17 17 18 21 22 ↓23 25

                     ↑

Q_{2} = 18

Q_{1} = \frac{16+17}{2} = 16.5

Q_{3} = \frac{22+23}{2} = 22.5

IQR = Q_{3} - Q_{1} = 22.5 - 16.5 = 6




4 0
2 years ago
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