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Kazeer [188]
3 years ago
9

Layla right her scooter 360 miles every week, she rides 60 miles every 3 hours. At this rate, how many hours will take Layla to

ride 360miles.
Mathematics
2 answers:
galina1969 [7]3 years ago
6 0

Answer:

It will take Layla 6 hours to ride 360 miles

Step-by-step explanation:

kiruha [24]3 years ago
5 0
The answer is 18 hours. It takes her 3 hours for 60 miles. 60 times 6 equals 360. So she had to ride 60 miles 6 times to get to 360 miles. Which means 6 times 3. So your answer is 18 hours.
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What does the ! Mean
Alina [70]

Answer:

!  means factorial . For example 3! (factorial 3) = 3*2*1 = 6

Answer to 14C3 is 364

Step-by-step explanation:

14! = 14*13*12*11*10*9*8*7*6*5*4*3*2*1

14C3 =   14*13*12*11*10*9*8*7*6*5*4*3*2*1 / 3*2*1 * 11*10*9*8*7*6*5*4*3*2*1

=    (14*13*12) /   3*2*1

= 14*13*2

=  364

3 0
3 years ago
PLSSSSSSS ASAPPPPPPPP<br><br><br> A)157<br> B)67<br> C)177<br> D)None of these answers <br> E)23
Helga [31]
23 is the answer for the problem
5 0
3 years ago
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gavin is making a flag for a school project. He has 3 1/6 ft of fabric. He used 2 1/2 ft to make the flag. How much fabric is re
Artyom0805 [142]

Answer:

he has 0.66 of fabrics remaining, 0.66 can be 33/50

Step-by-step explanation:

4 0
3 years ago
X+y+z=12<br> 6x-2y+z=16<br> 3x+4y+2z=28<br> What does x, y, and z equal?
lianna [129]

Answer:

x = 20/13 , y = 16/13 , z = 120/13

Step-by-step explanation:

Solve the following system:

{x + y + z = 12 | (equation 1)

6 x - 2 y + z = 16 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Swap equation 1 with equation 2:

{6 x - 2 y + z = 16 | (equation 1)

x + y + z = 12 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Subtract 1/6 × (equation 1) from equation 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+(4 y)/3 + (5 z)/6 = 28/3 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Multiply equation 2 by 6:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Subtract 1/2 × (equation 1) from equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

0 x+5 y + (3 z)/2 = 20 | (equation 3)

Multiply equation 3 by 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

0 x+10 y + 3 z = 40 | (equation 3)

Swap equation 2 with equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+8 y + 5 z = 56 | (equation 3)

Subtract 4/5 × (equation 2) from equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+(13 z)/5 = 24 | (equation 3)

Multiply equation 3 by 5:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+13 z = 120 | (equation 3)

Divide equation 3 by 13:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Subtract 3 × (equation 3) from equation 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y+0 z = 160/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Divide equation 2 by 10:

{6 x - 2 y + z = 16 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Add 2 × (equation 2) to equation 1:

{6 x + 0 y+z = 240/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Subtract equation 3 from equation 1:

{6 x+0 y+0 z = 120/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Divide equation 1 by 6:

{x+0 y+0 z = 20/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Collect results:

Answer:  {x = 20/13 , y = 16/13 , z = 120/13

8 0
3 years ago
Using the quadratic formula to solve 11x²-4x=1 What are The values of X?
Anvisha [2.4K]
11x^2 - 4x = 1
11x^{2} - 4x - 1 = 1 - 1
11x^{2} - 4x - 1 = 0
x = \frac{-(-4) \± \sqrt{(-4)^{2} - 4(11)(-1)}}{2(11)}
x = \frac{4 \± \sqrt{16 + 44}}{22}
x = \frac{4 \± \sqrt{60}}{22}
x = \frac{4 \± 2\sqrt{15}}{22}
x = \frac{2 \± \sqrt{15}}{11}
x = \frac{2 + \sqrt{15}}{11}\ \bold{or}\ x = \frac{2 - \sqrt{15}}{11}
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3 years ago
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