Answer:
Publishing results of research projects in peer-reviewed journals enables the scientific and medical community to evaluate the findings themselves. It also provides instructions so that other researchers can repeat the experiment or build on it to verify and confirm the results.
If he is jumping you are adding force which means that you will be falling twice as fast
Answer:
0.694 m
Explanation:
Case 1 : When only mass of 2.82 kg is hanged from spring
m = mass hanged from the spring = 2.82 kg
x = stretch caused in the spring = 0.331 m
k = spring constant
Using equilibrium of force in vertical direction
Spring force = weight of the mass
k x = m g
k (0.331) = (2.82) (9.8)
k = 83.5 N/m
Case 2 : When both masses are hanged from spring
m = mass hanged from the spring = 3.09 + 2.82 = 5.91 kg
x = stretch caused in the spring = ?
k = spring constant = 83.5 N/m
Using equilibrium of force in vertical direction
Spring force = weight of the mass
k x = m g
(83.5) x = (5.91) (9.8)
x = 0.694 m
Answer:
F = 3750 N
Explanation:
Given that,
Pressure, P = 150 Pa
Area, a = 25m²
We need to find the force applied. We know that, pressure is equal to the force acting per unit area. It can be given by :
So, the required force is 3750 N.
Answer:
C₂ = 2.22 KJ/kg °C
Explanation:
Since, both objects are in thermal contact. Therefore, the law of conservation of energy tells us that:
where,
m₁ = mass of ice = 1 kg
C₁ = specific heat of ice = 2.04 KJ/kg.°C
ΔT₁ = Change in Temperature of Ice = -8.88°C - (-24°C) = 15.12°C
m₂ = mass of metal block = 1 kg
C₂ = specific heat of metal = ?
ΔT₂ = Change in Temperature of Metal Block = 5°C - (-8.88°C) = 13.88°C
Therefore, using these values in the equation, we get:
<u>C₂ = 2.22 KJ/kg °C</u>
