Answer: the work done by the force is 0
Explanation:
F (x², xy)
121 = 11²
so R = x² + y² = 11²
p = x². Q = xy
Δp/Δy = 0, ΔQ/Δx
using Green's theorem
woek = c_∫F.Δr = R_∫∫ ΔQ/Δx - Δp/Δy) ΔA
= (x² + y² = 121)_∫∫ yΔA
now let x = rcosФ, y = rsinФ
ΔA = rΔrΔФ
so r from 0 to 11
and Ф from 0 to 2π
= 0_∫^2π 0_∫^11 rsinФ × rΔrΔФ
= 0_∫^2π SinФΔФ 0_∫^11 r²Δr
= [ -cosФ]^2π_0 [r³/3]₀¹¹ = ( -cos2π + cos0) (11³/3) = 0
therefore the work done by the force is 0
Answer:
5.1 m/s
Explanation:
The figure is missing: find it in attachment.
In order to find the average speed, we have to calculate the length of the total path, and divide it by the total time elapsed.
The curve from A to B is a quarter of a circle with a radius of r = 20 m, so its length is:

The path BC is the hypothenuse of a right triangle with sides equal to 20 m and 30 m, so its length is

Finally, the length of the path AC is the sum of the side of 30 m and the radius of the curve, so

So the total distance covered is

The total time elapsed is

So, the average speed is

Answer:
A negative charge, if free to move in an electric field, will move from a low potential point to a high potential point. To move a positive charge against the electric field, work has to be done by you or a force external to the field.
Explanation:
Mark as Brainliest plz!!!
First one I believe but im not completely sure