Question

Where does a hole occur in the graph of y = x(x+2) / x(x-3)

Answer 1

Answer:

A

Step-by-step explanation:

Given

y = $\frac{x(x+2)}{x(x-3)}$ ← cancel x on numerator/ denominator

 = $\frac{x+2}{x-3}$

Cancelling the factor x, leaves a hole in the graph at x = 0