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3 years ago

Where does a hole occur in the graph of y = x(x+2) / x(x-3)

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

7 0

Answer:

Step-by-step explanation:

Given

y = $\frac{x(x+2)}{x(x-3)}$ ← cancel x on numerator/ denominator

= $\frac{x+2}{x-3}$

Cancelling the factor x, leaves a hole in the graph at x = 0

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Solve the system of equations {3x-y=10, -x y=12} for Y

Novosadov [1.4K]

3x - y = 10 . . . (1)
-x + y = 12 . . . (2)

(1) + (2) => 2x = 22 => x = 22/2 = 11

From 2, -11 + y = 12 => y = 12 + 11 = 23

5 0

4 years ago

What is the length of s?

prisoha [69]

Answer:

20.78460969 = s

Step-by-step explanation:

tan theta = opposite side / adjacent side

tan 60 = s /12

Multiply each side by 12

12 tan 60 = s /12 *12

20.78460969 = s

8 0

3 years ago

What is the value of x? Enter your answer in the box. x =

Oliga [24]

$\star \blue{ \frak{To \: find :}}$

$\\ \\$

value of x

$\\ \\$

$\star \blue{ \frak{solution:}}$

$\\ \\$

So to find value of x , we have to apply Linear Pair.

$\\ \\$

Equation formed:

$\\ \\$

$\bigstar \boxed{ \tt(10x - 20) \degree + (6x + 8)\degree = 180 \degree} \\$

$\\ \\$

Step by step expansion:

$\\ \\$

$\dashrightarrow \sf(10x - 20) \degree + (6x + 8)\degree = 180 \degree \\$

$\\ \\$

$\dashrightarrow \sf10x - 20 \degree + 6x + 8\degree = 180 \degree \\$

$\\ \\$

$\dashrightarrow \sf10x +6x- 20 \degree + 8\degree = 180 \degree \\$

$\\ \\$

$\dashrightarrow \sf16x- 20 \degree + 8\degree = 180 \degree \\$

$\\ \\$

$\dashrightarrow \sf16x- 12\degree = 180 \degree \\$

$\\ \\$

$\dashrightarrow \sf16x = 180 \degree + 12\degree\\$

$\\ \\$

$\dashrightarrow \sf16x =192\degree\\$

$\\ \\$

$\dashrightarrow \sf \: x = \frac{192\degree}{16\degree} \\$

$\\ \\$

$\dashrightarrow \sf \: x = 12 \degree$

$\\ \\$

$\therefore \underline {\textsf{\textbf{Value of x is \red{12\degree}}}}$

4 0

2 years ago

Read 2 more answers

Starting with 10 blue balls, in each of 10 sequential rounds, we remove a random ball and replace it with a new red ball. For ex

s344n2d4d5 [400]

Answer:

Suppose the fraction of blue balls at any given state n is $f_{n}$ . At the start of the process we have: $f_{0}$ =1.

Now consider the situation after having drawn n times.

The current fraction of blue balls is $f_{n}$ , the number of blue balls is therefore 10 $f_{n}$ .

We either draw a red ball, with probability 1− $f_{n}$ . and the number of red balls, blue balls stay the same (we swap red for red):

$f_{n+1}$ (red)= $f_{n}$

or we draw a blue ball, with probability $f_{n}$ and we obtain 10 $f_{n}$ −1 blue balls on a total of 10 balls, thus:

$f_{n+1}$ (blue) = (10 $f_{n}$ − 1)/10

The total probability of (fraction of) blue balls after this n'th draw is therefore:

$f_{n+1}$ = $f_{n+1}$ (red)(1− $f_{n}$ )+ $f_{n+1}$ (blue) $f_{n}$

which can be simplified to:

$f_{n+1}$ =0.9 $f_{n}$

which leads to:

fn=0.9 $f_{n}$

At the end of the 10'th draw the fraction of blue balls is equal to:

$f_{10}$ = $0.9^{10}$ ≈ 0.348678

8 0

3 years ago

Does the following represent growth or decay y=4x

kari74 [83]

Hey there! :D

We can plug in numbers to see if it does.

y=4(1)

y=4

y=4(2)

y=8

This represents growth. When the input (x) increase, the output (y) increases.

I hope this helps!
~kaikers

4 0

3 years ago