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frosja888 [35]
3 years ago
13

Where does a hole occur in the graph of y = x(x+2) / x(x-3)

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
7 0

Answer:

A

Step-by-step explanation:

Given

y = \frac{x(x+2)}{x(x-3)} ← cancel x on numerator/ denominator

 = \frac{x+2}{x-3}

Cancelling the factor x, leaves a hole in the graph at x = 0

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The equation would be 4y=5x       4(x+15)=5x             x+15=y

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Check:

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