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DaniilM [7]
3 years ago
5

Ni

Chemistry
1 answer:
Alchen [17]3 years ago
5 0

Answer:

[Ar]3d^84s^2

Explanation:

From the question given, we are asked to write the condensed form of electronic configuration of nickel, Ni.

To do this, we simply write the symbol of the noble gas element before Ni in a squared bracket followed by the remaining electrons to make up the atomic number of Ni.

This is illustrated below:

The atomic number of Ni is 28.

The noble gas before Ni is Argon, Ar.

Therefore, the condensed electronic configuration of Ni is written as:

Ni(28) => [Ar]3d^84s^2

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The pH during the titration 30.0 mL OF 0.1000 M NaOH(aq) with 0.1000 M HCl(aq) of after 18.5 mL of the acid is added is : 12.38

<h3 /><h3>Calculate the pH value during the titration </h3>

<u>First step</u> : Determine the number of moles

Number of moles of NaOH = 0.1000 M * 30.00 mL = 3.0 mmol

Number of moles of HCl = 0.1000 M * 18.5 mL =  1.85 mmol

The net moles of NaOH = 3.0 mmol - 1.85 mmol = 1.15 mmol

<u>Next step :</u>

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[ NaOH ] = [ OH⁻ ] = net moles / total volume

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<u>Final step</u> : Determine the pH value

pOH = – log[OH⁻] = – log ( 0.023711 )

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pH value = 14 - pOH

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Hence we can conclude that The pH during the titration of after 18.5 mL of the acid is added is : 12.38

Learn more about pH : brainly.com/question/22390063

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