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4 years ago

What is the total number of sp2-hybridized carbon atoms present in the fluorophore used in the experiments

Chemistry

1 answer:

Mandarinka [93]4 years ago

3 0

Answer:

Explanation:

The structure of fluorophore used in the experiments has been drawn in the attachment. And from the drawing counting we can say that there are 9 sp2-hybridized carbon atoms present. Fiuorophores are a fluorescent chemical compound that can re-emit light upon light excitation. Normally used to produce absorbance and emission spectra.

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Consider the mixture of ethanol, c2h5oh, and o2. how many molecules of co2, h2o, c2h5oh, and o2 will be present if the reaction

Natali [406]

The reaction between ethanol and oxygen must be a combustion reaction to give carbon dioxide and water as products.

The reaction between ethanol, $C_2H_5OH$ and oxygen, $O_2$ is as follows:

$C_2H_5OH+O_2\rightarrow CO_2+H_2O$

In order to balance the reaction (the number of atoms of each element in the reaction are same on both the sides that is product and reactant), $O_2$ is multiplied by 3 in the reactant side and $CO_2$ is multiplied by 2 and $H_2O$ is multiplied by 3 on product side.

So, the balanced reaction is:

$C_2H_5OH+3O_2\rightarrow 2CO_2+3H_2O$

From the balanced reaction it is clear that 1 mole of $C_2H_5OH$ reacts with 3 moles of $O_2$ to give 2 moles of $CO_2$ and 3 moles of $H_2O$ .

Since, 1 mole = $6.022\times 10^{23}$ molecules (Avogadro's number)

So,

Number of molecules of $C_2H_5OH$ = $6.022\times 10^{23}$ molecules.

Number of molecules of $O_2$ = $6.022\times 10^{23}\times 3 = 18.066\times 10^{23}$ molecules.

Number of molecules of $CO_2$ = $6.022\times 10^{23}\times 2 = 12.044\times 10^{23}$ molecules.

Number of molecules of $H_2O$ = $6.022\times 10^{23}\times 3 = 18.066\times 10^{23}$ molecules.

3 0

3 years ago

Read 2 more answers

How does density differ from volume

natta225 [31]

Density: Degree of consistency measured by the quantity of mass per unit volume.

Volume: Amount of space something takes up.

6 0

3 years ago

Read 2 more answers

If element X has 38 protons, how many electrons does it have

Alla [95]

Answer:

38 electrons

Explanation:

They share the same amount.

5 0

3 years ago

A solution of 20.0 g of which hydrated salt dissolved in 200 g H2O will have the lowest freezing point?(A) CuSO4•5H2O(M=250)(B)

yarga [219]

Answer:

<em>The solution of Na₂SO₄ . 10H₂O </em>( choice D)<em>, will have the lowest freezing point.</em>

Explanation:

1) The lowering of the freezing point is a colligative property which means that it depends, and can be calculated from some contants of the pure solvent, and the number of solute particles dissolved.

ΔTf = m × Kf × i

Where, ΔTf is the reduction in the freezing point, m is the molality of the solution, Kf is the cryoscopic constant of the solvent, and i is the Van't Hoff factor.

2) Find the molality of each solution, m:

Formulae:

moles of solute, n = mass in grams / molar mass

m = n / kg of solvent

(A) CuSO₄•5H₂O (M=250)

n = 20.0 g / 250 g/mol = 0.0800 mol

m = 0.0800 mol / 0.200 kg = 0.400 m

(B) NiSO₄•6H₂O(M=263)

n = 20.0 g / 263 g/mol = 0.0760 mol

m = 0.0760 mol / 0.200 kg = 0.380 m

(C) MgSO₄•7H₂O (M=246)

n = 20.0 g / 246 g/mol = 0.0813 mol

m = 0.0813 mol / 0.200 kg = 0.406 m

(D) Na₂SO₄ • 10 H₂O (M = 286)

n = 20.0 g / 286 g/mol = 0.0699 mol

m = 0.0699 mol / 0.200 kg = 0.350 m

3) Van't Hoff factor.

Since, all the solutes are ionic, you start assuming that they all dissociate 100%.

That means that:

Each unit of CuSO₄.5H₂O yields 2 ions in water ⇒ i = 2

Each unit of NiSO₄. 6H₂O yileds 2 ions in water ⇒ i = 2

Each unit of MgSO₄.7H₂O yields 2 ions in water ⇒ i = 2

Each unit of Na₂SO₄.10H₂O yields 3 ions in water ⇒ i = 3

4) Comparison

Being Kf a constant for the four solutions (same solvent), you just must compare the product m × i

CuSO₄.5H₂O: 2 × 0.400 = 0.800

NiSO₄. 6H₂O: 2 × 0.380 = 0.760

MgSO₄.7H₂O: 2 × 0.406 = 0.812

Na₂SO₄.10H₂O: 3 × 0.406 = 1.218

As you see from above calculations, the dissociation factor defines the situation, and you can conclude that the last choice, i.e. the solution of Na₂SO₄ . 10H₂O, will have the greatest decrease of the freezing point, resulting in the lowest freezing point.

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4 years ago

An isotope has a half-life of 2 days. How much will be left after 6 days?

Stells [14]

I think the answer is C) 1/8, I’m sorry if it’s wrong

3 0

3 years ago