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damaskus [11]
3 years ago
12

I NEED HELP ANSWERING THESE QUESTIONS FOR 50 POINTS!!!!!

Chemistry
2 answers:
Semmy [17]3 years ago
7 0
The answers are true, true, false, true, and false.
dmitriy555 [2]3 years ago
3 0

Answer:

true true false true and true false

Explanation:

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A buffer is prepared by adding 300. 0 ml of 2. 0 mnaoh to 500. 0 ml of 2. 0 mch3cooh. what is the ph of this buffer? ka= 1. 8 10
Anton [14]

The Henderson-Hasselbalch equation can be used to determine the pH of the buffer from the pKa value. The pH of the buffer will be 4.75.

<h3>What is the Henderson-Hasselbalch equation?</h3>

Henderson-Hasselbalch equation is used to determine the value of pH of the buffer with the help of the acid disassociation constant.

Given,

Acid disassociation constant (ka) = 1. 8 10⁻⁵

Concentration of NaOH = 2.0 M

Concentration of CH₃COOH = 2.0 M

pKa value is calculated as,

pKa = -log Ka

pKa = - log (1. 8 x 10⁻⁵)

Substituting the value of pKa in the Henderson-Hasselbalch equation as

pH = - log (1. 8 x 10⁻⁵) + log [2.0] ÷ [2.0]

pH = - log (1. 8 x 10⁻⁵) + log [1]

= 4.745 + 0

= 4.75

Therefore, 4.75 is the pH of the buffer.

Learn more about the Henderson-Hasselbalch equation here:

brainly.com/question/27751586

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1 year ago
Mg + 2HCl ⟶ MgCl2 + H2
Ivanshal [37]

Answer: m = 24.31 g/mol · 1.13 mol

Explanation: 2 mol HCl use 1 mol Mg.

Magnesium is used 0.5 · 2.26 mol = 1.13 mol

M(Mg) = 24.31 g/ mol

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