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Genrish500 [490]
3 years ago
5

Una tirolina de 26 m de largo está atada entre dos postes que están separados por 24 m. Si Manuela monta la tirolina desde el pr

imer poste a una altura de 50 m, ¿cuál es la diferencia entre los dos postes?
Mathematics
1 answer:
maks197457 [2]3 years ago
4 0

Answer:

The difference between the heights of the poles is 10m

Step-by-step explanation:

The distance between poles is 24 m

The length of the cable is 26m

You first use the Pythagoras' theorem to calculate the vertical distance between the end of one pole and the end of the other one.

c_2=\sqrt{h^2-c_1^2}\\\\c_2=\sqrt{(26m)^2-(24m)^2}=\sqrt{100}m=10m

The difference between the heights of the poles is 10m

The higher pole has height of 50m

Then, the lower pole has a height of 50m - 10m = 40m

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The sum of three consecutive odd integers is-219. What is the first number in the set?
Alex73 [517]

Answer:

-75

Step-by-step explanation:

Let us consider the first  odd number to be 'x'.

Thus:

  1. 1st odd number: x
  2. 2nd odd number: x+2
  3. 3rd odd number: x+3

According to the question, the sum of these three consecutive ODD numbers should be equal to -219

So,

x + x + 2 + x + 4 = -219

3x + 6 = -219

3x = -225

x = -75

3 0
3 years ago
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Rina8888 [55]
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3 0
3 years ago
1. Consider the function f(x) = x² – 9. Algebraically determine the domain of y = Vf(x) . State using set notation.
AfilCa [17]

Answer:

-3<x<3

Step-by-step explanation:

let y=0

0=x^2-9

0=(x+3)(x-3)

x=-3 and x=+3

8 0
3 years ago
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Mrac [35]
5y + 4 = 6x-8 would be it
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3 years ago
An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est
MrRa [10]

Answer:

<em> 85% level of the confidence interval is</em>

<em>(26.337, 26.662)</em>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given the size of the sample 'n' = 295

Mean of the sample x⁻ = 26.5

The Standard deviation of the Population = 2.7

85% level of the confidence interval is determined by

(x^{-} - Z_{0.15} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.15} \frac{S.D}{\sqrt{n} })

Critical value Z₀.₁₅ = 1.036

<em> 85% level of the confidence interval is determined by</em>

(x^{-} - Z_{0.15} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.15} \frac{S.D}{\sqrt{n} })

(26.9 -1.036 \frac{2.7}{\sqrt{295} } , 26.5 + 1.036 \frac{2.7}{\sqrt{295} })

( 26.5 - 0.1628 , 26.5+0.1628)

(26.3372,26.6628)

7 0
3 years ago
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