Answer:
Step-by-step explanation:

the complete question is
Find two numbers whose difference is 46 and whose product is a minimum
Let
x------->larger number
y-------> smaller number
P-------> product of the two numbers
we know that
-----> equation 1
-----> equation 2
substitute equation 1 in equation 2
![P=x*[x-46]\\ P=x^{2} -46x](https://tex.z-dn.net/?f=%20P%3Dx%2A%5Bx-46%5D%5C%5C%20P%3Dx%5E%7B2%7D%20-46x%20)
using a graph tool
see the attached figure
Find the value of x for that the product P is a minimum
the vertex is the point 
that means, for 
the product is a minimum 
find the value of y

therefore
the answer is
the numbers are
and 
You can also do the division with remainders to find the answer:
195 ÷ 96 = 2,041666666666667
So you can clearly see that there are more than two but less than three 96s in 195. So multiply 96 by 2 and then substract the result from 195 to find the remainder:
96 * 2 = 192
195 - 192 = 3
It means that in 195 there will fit two 96s with a remainder of 3.
We can also write it as two 96s and 3/96, what can be further simplified to two 96s and 1/32.
Answer:
3.17
Step-by-step explanation:
2.5/1.5 = 1.66667, 1.66667 (it goes on infinitely 1.6666 etc.)
1.66667 x 1.9 = 3.166666654, and when rounded to nearest tenth it is 3.17