The point that divides AB into a 3:2 ratio is calculated by (d) for a ratio of 3:2, divide AB into 5 equal parts. Each equal part is 2 units, so the point that divides AB into a 3:2 ratio is 2
<h3>How to determine the ratio?</h3>
The given parameters are:
A = -4
B = 6
Start by calculating the length AB using:
AB = |B - A|
This gives
AB = |6 -(-4)|
Evaluate
AB = 10
Next, the length is divided into 5 parts.
So, the length of each part is:
Length = 10/5
Length = 2
The point on the location 3 : 2 is then calculated as:
Point = A + 3 * Length
This gives
Point = -4 + 3 * 2
Evaluate
Point = 2
The above computation is represented by option (d)
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X=-3y+6 That is the answer.
If p = 2, insert the value of p.
2^3 = 2 x 2 x 2 = 4 x 2 = 8
so p^3 = 8
Answer:
∴Given Δ ABC is not a right-angle triangle
a= AB = √45 = 3√5
b = BC = 12
c = AC = √45 = 3√5
Step-by-step explanation:
Given vertices are A(3,3) and B(6,9)
AB = 
Given vertices are B(6,9) and C( 6,-3)
= 
BC = 12
Given vertices are A(3,3) and C( 6,-3)
AC² = AB²+BC²
45 = 45+144
45 ≠ 189
∴Given Δ ABC is not a right angle triangle
