Answer:
The terms used to describe the given process in <em><u>Chemical weathering.</u></em>
Explanation:
Weathering of rock is defined as breaking down of the rock into small pieces.
There are two types pf weathering :
Mechanical weathering : This weathering is due to change in physical parameters : temperature change, pressure change etc.
For example : When water soaked up in cracks or crevices of rocks freezes it expands and physically breaks the rock.
Chemical weathering : This weathering is decomposition of rocks due to action of chemicals.This type of weathering also changes chemical composition of rocks.
For example : when gases like carbon dioxide, sulfur oxide get dissolves in water present in rock to form weak acid which ease up the dissolving of rock in that weak acid.
Explanation:
It is known that for a body centered cubic unit cell there are 2 atoms per unit cell.
This means that volume occupied by 2 atoms is equal to volume of the unit cell.
So, according to the volume density
2 atoms =
=
Formula for volume of a cube is . Therefore,
Volume of the cube =
As lattice constant (a) =
=
Therefore, the value of lattice constant is .
And, for bcc unit cell the value of radius is as follows.
r =
Hence, effective radius of the atom is calculated as follows.
r =
=
=
Hence, the value of effective radius of the atom is .
Temperature affects magnetism by either strengthening or weakening a magnet's attractive force. A magnet subjected to heat experiences a reduction in its magnetic field as the particles within the magnet are moving at an increasingly faster and more sporadic rate.
The atomic number is the same as the amount of electrons and protons. For example:
Oxygens atomic number is 8 so the proton and electron count is 8.
Hydrogens atomic number is 1 so the proton and electron count is 1.
Answer:
Explanation:
Let’s call water Component 1 and lactose Component 2.
According to Raoult’s Law,
where
p₁ and p₂ are the vapour pressures of the components above the solution
χ₁ and χ₂ are the mole fractions of the components
p₁° and p₂° are the vapour pressures of the pure components.
Data:
m₁ = 110.0 g; p₁° = 118.0 torr
m₂ = 50.00 g; p₂° = 0 torr
1. Calculate the moles of each component
2. Calculate the mole fraction of each component
3. Calculate the vapour pressure of the mixture