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kondaur [170]
3 years ago
14

The volume density of atoms for a bcc lattice is 5 x 1026 m-3. Assume that the atoms are hard spheres with each atom touching it

s nearest neighbors. Determine the lattice constant and effective radius of the atom.
Chemistry
1 answer:
ollegr [7]3 years ago
3 0

Explanation:

It is known that for a body centered cubic unit cell there are 2 atoms per unit cell.

This means that volume occupied by 2 atoms is equal to volume of the unit cell.

So, according to the volume density

        5 \times 10^{26} atoms = 1 [tex]m^{3}

        2 atoms = \frac{1 m^{3}}{5 \times 10^{26} atoms} \times 2 atoms

                     = 4 \times 10^{-27} m^{3}

Formula for volume of a cube is a^{3}. Therefore,

           Volume of the cube = 4 \times 10^{-27} m^{3}

As lattice constant (a) = (4 \times 10^{-27} m^{3})^{\frac{1}{3}}

                                   = 1.59 \times 10^{-9} m

Therefore, the value of lattice constant is 1.59 \times 10^{-9} m.

And, for bcc unit cell the value of radius is as follows.

                 r = \frac{\sqrt{3}}{4}a

Hence, effective radius of the atom is calculated as follows.

                 r = \frac{\sqrt{3}}{4}a

                   = \frac{\sqrt{3}}{4} \times 1.59 \times 10^{-9} m

                   = 6.9 \times 10^{-10} m

Hence, the value of effective radius of the atom is 6.9 \times 10^{-10} m.

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6 0
3 years ago
Write the balanced equation. Then calculate the volume of 0.65 M HCl required to completely neutralize 400.0 ml of 0.88 M KOH.
Misha Larkins [42]
Hello!

The balanced equation for the neutralization of KOH is the following:

HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)

To calculate the volume of HCl required, we can apply the following equation:

 moles HCl = moles KOH \\  \\ cHCl*vHCl=cKOH*vKOH \\  \\ vHCl= \frac{cKOH*vKOH}{cHCl}= \frac{400 mL*0,88M}{0,65M}=  541,54mL

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8 0
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1. A solution with a pH of 9 has a pOH of
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Answer:

strength = 10⁻²/10⁻³ = 10 times more acidic

Explanation:

1. A solution with a pH of 9 has a pOH of

pH + pOH = 14 => pOH = 14 - pH = 14 - 9 = 5

2. Which is more acidic, a solution with a pH of 6 or a pH of 4?

pH of 4 => Higher [H⁺] = 10⁻⁴M vs pH of 6 => [H⁺] = 10⁻⁶M

3. How many times more acidic is a solution with a pH of 2 than a solution with a pH of 3?

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soln with pH = 3 => [H⁺] = 10⁻³M

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5. A solution has a pOH of 9.6. What is the pH? (Use the formula.)

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The amount of energy released is calculated by the product of heat of fusion and mass. The formula of amount energy released is given by: q= L\times m                (1)

Here,  

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q= 334 J/g \times 65.8 g

q= 21977.2 Joules ≅ 21977 Joules

q= 21977 Joules

Thus, amount of energy released is 21977 Joules


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