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hammer [34]
3 years ago
6

i have a question about atoms. How would i find electrons when the atomic number is the number of protons and electrons?

Chemistry
1 answer:
andre [41]3 years ago
3 0

The atomic number is the same as the amount of electrons and protons. For example:
Oxygens atomic number is 8 so the proton and electron count is 8.
Hydrogens atomic number is 1 so the proton and electron count is 1.
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Answer:  a) Sodium and nitrogen : NaN_3  : sodium nitride.

b) Oxygen and strontium : SrO :  strontium oxide.

c) Aluminum and chlorine : AlCl_3  : aluminium chloride.

d) Cesium and bromine : CsBr  : cesium bromide.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

a) Sodium and nitrogen : Here sodium is having an oxidation state of +1 called as Na^{+} cation and nitrogen forms an anion N^{3-} with oxidation state of -3. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral NaN_3  named as sodium nitride.

b) Oxygen and strontium : Here strontium is having an oxidation state of +2 called as Sr^{+} cation and oxygen forms an anion O^{2-} with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral SrO  named as strontium oxide.

c) Aluminum and chlorine : Here aluminium is having an oxidation state of +3 called as Al^{3+} cation and chlorine forms an anion Cl^{-} with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral AlCl_3  named as aluminium chloride.

d) Cesium and bromine : Here cesium is having an oxidation state of +1 called as Cs^{+} cation and bromine forms an anion Br^{-} with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral CsBr  named as cesium bromide.

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Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial.
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/watch?v=DLzxrzFCyOs

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STOP IMAGINING

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